我想缩短或以某种方式提高自己的汇编程序 [英] I want to shorten or somehow improve my assembly program

问题描述

我已经创建了打印从1到1000的整数无5.印刷倍数它工作正常，但我想以某种方式缩短我的code或使其以任何方式可能更好汇编程序。我是新来组装，这是我第一次创建一个使用ARMsim程序。

  .EQU SWI_PrStr，0×69
.EQU SWI_PrInt，0x6b
.EQU标准输出，1
.EQU SWI_EXIT，为0x11。全球_start
开始：MOV R5，＃1
MOV R6，＃1
MOV R7，＃1000LOOPHERE：CMP R5，R7
BLE LOOPBODY
乙LOOPDONELOOPBODY：CMP R6，＃5
BLT LOOPIF
MOV R6，＃0
乙LOOPNEXTLOOPIF：MOV R0，#StDout
MOV R1，R5
SWI SWI_PrIntLDR R1，= EOL
SWI SWI_PrStr乙LOOPNEXTLOOPNEXT：ADD R5，R5，＃1
ADD R6，R6，＃1
乙LOOPHERELOOPDONE：
SWI SWI_EXIT。数据EOL：.asciz\\ n
。结束
 

解决方案

关键是使用条件指令，使得ARM汇编从其他架构完全不同。

 启动：
    MOV R0，#StDout
    MOV R5，＃0;主计数器
    MOV R4，＃5，模5计数器
循环：
    加R5，＃1
    潜艇R4，＃1;更新计数器
    moveq R4，＃5    movne R1，R5
    猪SWI_PrInt;打印;如果不倍数5
    ldrne R1，= EOL
    猪SWI_PrStr    CMP R5，＃1000;循环播放，直到我们到达1000
    BNE循环
 

i have created an assembly program that prints integers from 1 to 1000 without printing multiples of 5. it works fine but i would like to somehow shorten my code or make it better in any way possible. i am new to assembly and this is my first time creating a program using ARMsim.

.equ SWI_PrStr, 0x69
.equ SWI_PrInt, 0x6b
.equ StDout, 1
.equ SWI_EXIT, 0x11

.global _start
start:

MOV R5, #1
MOV R6, #1
MOV R7, #1000

LOOPHERE:

CMP R5, R7
BLE LOOPBODY
B LOOPDONE

LOOPBODY:

CMP R6, #5
BLT LOOPIF
MOV R6, #0
B LOOPNEXT

LOOPIF:

MOV R0, #StDout
MOV R1, R5
swi SWI_PrInt

ldr R1, =EOL
swi SWI_PrStr

B LOOPNEXT

LOOPNEXT:

ADD R5, R5, #1
ADD R6, R6, #1
B LOOPHERE

LOOPDONE:
swi SWI_EXIT

.data

EOL: .asciz "\n"
.end

解决方案

The key is to use the conditional instructions that makes ARM assembly so different from other architectures.

start:
    mov    r0, #StDout
    mov    r5, #0       ;Main Counter
    mov    r4, #5       ;Modulo-5 counter
loop:
    add    r5, #1
    subs   r4, #1       ;Update counters
    moveq  r4, #5

    movne  r1, r5
    swine  SWI_PrInt    ;Print number if not multiple of 5
    ldrne  r1, =EOL
    swine  SWI_PrStr

    cmp    r5, #1000     ;Loop until we reach 1000
    bne    loop

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