在搜索-lcudart时跳过不兼容的libcudart.so [英] skipping incompatible libcudart.so when searching for -lcudart

问题描述

当我使用nvcc 5.0编译.cu文件时，编译器会给我以下信息。

When I compile .cu file with nvcc 5.0, the compiler gives me following information.

/ usr / bin / ld：skip在搜索-lcudart时不兼容/usr/local/cuda-5.0/lib/libcudart.so

/usr/bin/ld: skipping incompatible /usr/local/cuda-5.0/lib/libcudart.so when searching for -lcudart

似乎是警告或错误。我不知道事情是什么。

It seems either a warning or an error. I don't know what the matter is.

有没有人知道有关此信息的更多详细信息？

Is there anyone knowing more details about this information?

推荐答案

当尝试将64位代码与32位库链接时，通常会发生此警告，请参阅以下问题：跳过不兼容的库编译。

This warning often happens when trying to link a 64-bit code with a 32-bit library, see this question: Skipping Incompatible Libraries at compile.

您需要区分两个库文件：

You need to distinguish 2 library files:

• $ CUDA_HOME / lib / libcudart.so 是32位版本的 cudart 库。


• $ CUDA_HOME / lib64 / libcudart.so 是 cudart 库的64位版本。

• $CUDA_HOME/lib/libcudart.so, the 32-bit version of the cudart library.
• $CUDA_HOME/lib64/libcudart.so, the 64-bit version of the cudart library.

（在您的情况下， $ CUDA_HOME 是 / usr / local /cuda-5.0 ）

基本上，链接器首先找到32位库（ -L

Basically, the linker finds the 32-bit library first (-L options are searched in order) and returns that warning even if it ends up finding the proper library.

您可能需要添加选项， $ CUDA_HOME / lib 到环境变量$ $ CUDA_HOME / lib64 code> ld 可以在32位版本之前为您的64位架构找到合适的库。

You probably need to add $CUDA_HOME/lib64 to your LD_LIBRARY_PATH environment variable before $CUDA_HOME/lib so that ld can find the proper library for your 64-bit architecture before the 32-bit version.

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