不允许指向不完整类类型的指针 - 单向链表 [英] pointer to incomplete class type is not allowed - singly linked list

问题描述

我正在尝试创建一个简单的单向链表.以前，我成功地做到了这一点，没有错误，但是现在我遇到了错误.由于第 23 行中的 if 语句，我怀疑内存分配存在某种问题.

I'm trying to create a simple singly linked list. Previously, I successfully did this with no errors, however now I encounter an error. I suspect that there is some kind of problem with memory allocation because of the if statement in line 23.

我尝试过的:

1. 我在所有声明中都使用了类型转换，即使在 C 中没有必要.

1. I used typecasting in all of my declarations even though it is not necessary in C.

我删除了 if 语句，但仍然遇到错误.

I removed the if statement and I still encountered the errors.

这是我的代码:

#include <stdio.h>
#include <stdlib.h>

typedef struct
{
    int value;
    struct Product *next;

} Product;

int main()
{
    int user_choice;
    Product *head;

    head = malloc(sizeof(Product));
    head->next = NULL;
    head->value = 5;

    printf("\n Do you want to add a new node (0 for no, 1 for yes)? \n");
    scanf("%d", &user_choice);

    if (user_choice == 1) // line 23
    {
        head->next = malloc(sizeof(Product));

        if (!head->next)
            printf("\n Memory allocation failed! \n");

        head->next->next = NULL; // 1st error 

        printf("\n Enter a value: \n");

        int value;
        scanf("%d", &value);

        head->next->value = value; // 2nd error
    }

    free(head);
    free(head->next);
}

推荐答案

typedef struct
{
} Product;

为一个 unnamed 结构声明一个名为 Product 的类型别名 - 但是你需要一个 named 结构用于你的前向声明 struct Product*next;，否则编译器无法确定它属于哪个定义.

Declares a type alias called Product for an unnamed struct - however you need a named struct for your forward declaration struct Product *next;, otherwise the compiler cannot determine which definition it belongs to.

最简单的解决方案是给结构一个名字:

The simplest solution is to give the struct a name:

typedef struct Product
{
    int value;
    struct Product *next;
} Product;

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