使用 Nokogiri 获取节点的兄弟节点 [英] Getting the siblings of a node with Nokogiri

问题描述

有没有办法在一个节点中找到一个特定的值，然后返回它的所有兄弟值?

Is there a way to find a specific value in a node and then return all its sibling values?

例如，我想找到包含 ID 5678 的 id 节点，然后获取电子邮件地址和与 ID 5678 关联的所有图像.

For example, I would like to find find the id node that contains ID 5678 and then get the email address and all images associated with ID 5678.

Nokogiri::XML.parse(File.open('info.xml'))

这是一个示例 XML 文件.

Here's a sample XML file.

<xmlcontainer>
  <details>
    <id>1234</id>
    <email>[e-mail]</email>
    <image>images/1.jpg</image>
    <image>images/2.jpg</image>
    <image>images/3.jpg</image>
  </details>
  <details>
    <id>5678</id>   
    <email>[e-mail]</email>
    <image>images/4.jpg</image>
    <image>images/5.jpg</image>
  </details>
  <details>
    <id>9011</id>   
    <email>[e-mail]</email>
    <image>images/6.jpg</image>
    <image>images/7.jpg</image>
  </details>
</xmlcontainer>

推荐答案

require 'nokogiri'
doc = Nokogiri::XML.parse(File.open('info.xml'))
details = doc.css('details').find{|node| node.css('id').text == "5678"}
email = details.css('email').text # => "[e-mail]"
images = details.css('image').map(&:text) # => ["images/4.jpg", "images/5.jpg"]

更新:有更短的、可以说更好的方法来获取你想要的details节点:

Update: There are shorter, arguably better, ways to grab the details node you want:

details = doc.at('details:has(id[text()="5678"])')

或

details = doc.search('id[text()="5678"] ~ *')

这些都是由 pguardiario 提供的.

Those are both courtesy of pguardiario.

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