使用XPath选择两个节点之间的兄弟节点 [英] Selecting siblings between two nodes using XPath

问题描述

如何选择id为header_completed的表与header_completed中的中心对齐后的第一个表之间的所有表？这里是我选择它的html：

 < table border =0cellpadding =0cellspacing = 0width =920align =center>< / table> 
< table border =0cellpadding =0cellspacing =0width =920>< / table> 
< table border =0cellpadding =0cellspacing =0width =920>< / table> 
< table border =0cellpadding =0cellspacing =0width =920align =centerclass =header_completed>< / table> 
< table border =0cellpadding =0cellspacing =0width =920>< / table> <  -  
< table border =0cellpadding =0cellspacing =0width =920>< / table> <  -  
< table border =0cellpadding =0cellspacing =0width =920>< / table> <  - 这5 
< table border =0cellpadding =0cellspacing =0width =920>< / table> <  -  
< table border =0cellpadding =0cellspacing =0width =920>< / table> <  -  
< table border =0cellpadding =0cellspacing =0width =920align =center>< / table> 
< table border =0cellpadding =0cellspacing =0width =920>< / table> 
< table border =0cellpadding =0cellspacing =0width =920>< / table> 
< table border =0cellpadding =0cellspacing =0width =920align =center>< / table> 
  

我尝试使用 // table [@ id =header_completed] / following-sibling :: node（）[following-sibling :: table [@ align =center] [1]] 但它没有用。

解决方案

我相信这个XPath表达式会选择你想要的节点：

  // table [@ class =header_completed] / 
 following-sibling :: table [@ align =center] [1] / 
 before-sibling :: table [
先前的sibling :: table [@ class =header_completed] 
] 
  

使用 @ class =header_completed导航到表。

从那里我选择了第一个下面的兄弟表，其中 @ align =center。

我选择所有前面的兄弟表，它们都有一个前面的兄弟表，这个表是 @ class =header_completed。

How would I select all the tables between the table whose id is header_completed and the first table after the header_completed one that has an align of center? Here is the html I am selecting it from:

<table border="0" cellpadding="0" cellspacing="0" width="920" align="center"></table>
<table border="0" cellpadding="0" cellspacing="0" width="920"></table>
<table border="0" cellpadding="0" cellspacing="0" width="920"></table>
<table border="0" cellpadding="0" cellspacing="0" width="920" align="center" class="header_completed"></table>
<table border="0" cellpadding="0" cellspacing="0" width="920"></table> <--
<table border="0" cellpadding="0" cellspacing="0" width="920"></table> <--
<table border="0" cellpadding="0" cellspacing="0" width="920"></table> <-- these 5
<table border="0" cellpadding="0" cellspacing="0" width="920"></table> <--
<table border="0" cellpadding="0" cellspacing="0" width="920"></table> <--
<table border="0" cellpadding="0" cellspacing="0" width="920" align="center"></table>
<table border="0" cellpadding="0" cellspacing="0" width="920"></table>
<table border="0" cellpadding="0" cellspacing="0" width="920"></table>
<table border="0" cellpadding="0" cellspacing="0" width="920" align="center"></table>

I tried using //table[@id="header_completed"]/following-sibling::node()[following-sibling::table[@align="center"][1]] but it didn't work.

解决方案

I believe this XPath expression selects the nodes you want:

//table[@class="header_completed"]/
    following-sibling::table[@align="center"][1]/
        preceding-sibling::table[
            preceding-sibling::table[@class="header_completed"]
        ]

First I navigate to the table with @class="header_completed".

From there I select the first following sibling table with @align="center".

From there I select all preceding sibling tables that have a preceding sibling which is the table with @class="header_completed".

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