获取元素的值而不解析ios中的所有xml文件 [英] Get value of an element without parse all xml file in ios
问题描述
我想知道是否有可能,在不使用所有委托 NSXMLParse 方法的情况下获取 xml 文件的特定元素值,我知道在 OS X 中可以通过两个简单的行:
i want know if is possible, to get a specific element value of a xml file without use all delegate NSXMLParse method, i know that in OS X is possible with two simple line:
NSXMLDocument *xmlDoc = [[NSXMLDocument alloc] initWithData:connection.data options:0 error:nil];
NSString *time = [[xmlDoc rootElement] stringValueForXPath:@"./Time"];
可以在 iOS 中做同样的事情吗?几行?
is possible do the same thing in iOS? with few line?
谢谢
推荐答案
XPath 也适用于 iOS.这是一个关于使用 libxml2、XPath 和 XML 解析数据的非常棒的教程.
XPath exists for iOS, as well. Here is a really great tutorial on using libxml2, XPath, and XML for parsing data.
使用 XPath,您需要传入剪辑查询.对于以下 XML,您的剪辑查询将是//day":
With XPath, you're expected to pass in a clip query. For the following, XML, your clip query would be "//day":
<day>
Monday
</day>
<day>
Tuesday
</day>
...
<day>
Friday
</day>
这将为您提供一个包含 5 个字典的数组,其中 node_name = day 和 node_content = 星期几.
This will give you an array of 5 dictionaries with node_name = day and node_content = the day of the week.
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