Java:如果十进制为0，如何将双精度数输出为整数格式 [英] Java: how to output double-type number to integer format if its decimal is 0

问题描述

我有一个双类型数字数组 {1.0, 2.3, 3.45, 7.8, 9.0, 5.0}.输出数字时，我希望小数点为 0 的数字显示为整数:例如，1.0 => 1、9.0 => 9.

I have an array of double-type numbers {1.0, 2.3, 3.45, 7.8, 9.0, 5.0}. When outputting the numbers, I want to have those with decimal of 0 to show up like an integer: for example, 1.0 => 1, 9.0 => 9.

在java中，你如何轻松地做到这一点?谢谢

In java, how do you do this easily? thanks

推荐答案

我建议不要使用任何库:

Not using any libraries I'd suggest:

public static String parse(double num) {
    if((int) num == num) return Integer.toString((int) num); //for you, StackOverflowException
    return String.valueOf(num); //and for you, Christian Kuetbach
}

将 double 转换为 int 会截断小数位.

Casting a double to int will cut off decimal places.

随意将数字转换为字符串；)

Feel free to convert the number to a string in whatever way you please ;)

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