私有静态最终双精度数为0 [英] private static final double is 0

问题描述

我正在尝试使用以下行指定一个双精度常量，有人可以帮我解释一下为什么在运行时此常量的值为0.0:

I am trying to use the following line to specify a double constant, can anybody help explain to me why at runtime this constant has a value of 0.0:

private static final double CONSTANT = 1/2;

推荐答案

1和2被解释为整数，并产生除法的整数结果.在末尾添加D，以使它们解释为双精度.

1 and 2 are interpreted as integers and produce integer result of division. Add D at the end to make them interpreted as doubles.

private static final double CONSTANT = 1D/2D;

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