数字读取和输出 [英] number read and output

问题描述

好的，我遇到了一些麻烦，我可以让程序读取所有整数，但现在我很困惑如何让程序读取奇数或偶数，然后只添加奇数和偶数，给出总计两者

Ok I'm having a little trouble I can get the program to read all the integers but now I'm confused how to get the program to read that is odd or even then add only odd and only even, giving totals for both

 def main():
      myfile = open('numbers.txt','r')
      for line in myfile:
          print(line)
      myfile.close()
      myfile=open('numbers.txt','r')
      num1=int(myfile.readline())
      num2=int(myfile.readline())
      num3=int(myfile.readline())
      num4=int(myfile.readline())
      num5=int(myfile.readline())
      num6=int(myfile.readline())
      num7=int(myfile.readline())
      num8=int(myfile.readline())
      num9=int(myfile.readline())
      num10=int(myfile.readline())
      num11=int(myfile.readline())
      num12=int(myfile.readline())
      myfile.close()

      total=num1+num2+num3+num4+num5+num6+num7+num8+num9+num10+num11+num12
      print('The numbers are:',num1,num2,num3,num4,num5,num6,num7,num8,num9,num10,num11,num12)
      print('Their total is:',total)

  main()

推荐答案

这里有一个解决方案，避免使用太多变量:

here is a solution, to avoid using too many variables:

def getOddEven(fileName):
    odd = 0
    even = 0
    print ('The numbers are: ')
    with open(fileName, 'r') as myfile:
        for line in myfile:
            print(line),
            try:
                number = int(line)
                if (number%2 == 0):
                    even+=number
                else:
                    odd+=number
            except:
                pass
    return odd,even

def main():
    odd, even = getOddEven('numbers.txt')
    print('\nTheir total is:',odd + even)
    print('Total of odd numbers is: ', odd)
    print('Total of even numbers is: ', even)

if __name__ == '__main__':
    main()

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