正则表达式块否定 [英] Regular Expression block negation

问题描述

我想找出一个没有出现特定标签的字符串，例如:

I want to find out a string in which a particular tag does not occur, such as:

<xyz>[\w]+<[^(unwanted)]></xyz>

其中 unwanted 将被解释为 a, d, e, n>、t 和 u.但我想要的是一个块字符串.我如何用正则表达式表达它?我试过消极前瞻，但不起作用:

where unwanted will be interpreted as a, d, e, n, t and u. But what I want is a block string. How can I express it in regular expression? I have tried negative lookahead, which doesn't work:

<xyz>.+(?!unwanted).+</xyz>

推荐答案

<xyz>(?:(?!unwanted).)+</xyz>

匹配 <xyz>...</xyz> 中的所有字符，但前提是表达式 unwanted 不以任何字符开头.

Matches all chars in <xyz>...</xyz>, but only as long as the expression unwanted doesn't start at any of them.

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