Matlab/Octave - 解析和绘制日期字符串与整数 [英] Matlab/Octave - parsing and plotting date string vs. integer

问题描述

我有一个数据文件，第一列是日期字符串，第二列是整数:

I have a data file with the first column as date strings and the second column an integer:

"2020/02/29" 1
"2020/03/03" 2
"2020/03/04" 6

我想解析这个文件并在 x 轴上绘制日期，在 y 轴上绘制整数.我最近一次失败的尝试是:

I want to parse this file and plot the date on the x-axis and the integer on the y-axis. My most recent failing attempt is:

file_name = "data.dat";
fid = fopen(file_name, 'rt');
raw_data = textscan(fid, "%s %d");
fclose(fid);

graphics_toolkit('gnuplot');
plot(raw_data(:, 1), raw_data(:, 2));

图表为空，没有可显示的数据.如何正确绘制此类数据?似乎 textscan 的输出对于绘图来说有点笨拙.

The graph is empty with no data to show. How can I properly plot such data? It seems the output of textscan is a little unwieldy for plotting.

推荐答案

不能绘制字符串，必须先将日期字符串转换为日期数字.使用 cellfun 来高效地做到这一点

you can't plot a string, you must convert the date string to a date number first. use cellfun to do this efficiently

x=cellfun(@(d) datenum(regexprep(d,'"',''),'yyyy/mm/dd'), raw_data{1});
y=raw_data{2};
plot(x,y)

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