如何在 OWL/GraphDB 中推断具有 2 个以上属性的个体? [英] How to infer individual with more than 2 properties in OWL / GraphDB?

问题描述

我从上一个问题那里得到了建议并修改了来源.但是，源仍然无法正常工作.

I got advice from the previous question and modified the source. However, the source still does not work properly.

我正在使用 GraphDB(规则集:OWL2-RL)和 SPARQL.

I am using GraphDB(RuleSet: OWL2-RL) and SPARQL.

我有一个包含 Person 和 Animal_Lover 类的本体.如果人们拥有超过 2 只宠物，则他们是 Animal_Lover.

I have an ontology with Person and Animal_Lover classes. People are Animal_Lover if they have more than 2 pet.

我怎样才能在我的本体中做到这一点?

How can I do this in my ontology?

<?xml version="1.0"?>
    <rdf:RDF xmlns="http://www.example.com/test"
       xmlns:test="http://www.example.com/test#"
       xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
       xmlns:owl="http://www.w3.org/2002/07/owl#"
       xmlns:xml="http://www.w3.org/XML/1998/namespace"
       xmlns:xsd="http://www.w3.org/2001/XMLSchema#"
       xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#">
<owl:Ontology rdf:about="http://www.example.com/test"/>

<owl:ObjectProperty rdf:about="http://www.example.com/test#hasOwner">
    <owl:inverseOf rdf:resource="http://www.example.com/test#hasPet"/>
</owl:ObjectProperty>

<owl:ObjectProperty rdf:about="http://www.example.com/test#hasPet">
    <owl:inverseOf rdf:resource="http://www.example.com/test#hasOwner"/>
</owl:ObjectProperty>

<owl:Class rdf:about="http://www.example.com/test#Animal_Lover">
    <owl:equivalentClass>
        <owl:Restriction>
            <owl:onProperty rdf:resource="http://www.example.com/test#hasPet"/>
            <owl:minQualifiedCardinality rdf:datatype="http://www.w3.org/2001/XMLSchema#nonNegativeInteger">2</owl:minQualifiedCardinality>
            <owl:onClass rdf:resource="http://www.example.com/test#Mammal"/>
        </owl:Restriction>
    </owl:equivalentClass>
    <rdfs:subClassOf rdf:resource="http://www.example.com/test#Person"/>
</owl:Class>

<owl:Class rdf:about="http://www.example.com/test#Mammal"/>

<owl:Class rdf:about="http://www.example.com/test#Dog">
    <rdfs:subClassOf rdf:resource="http://www.example.com/test#Mammal"/>
    <owl:disjointWith rdf:resource="http://www.example.com/test#Person"/>
</owl:Class>

<owl:Class rdf:about="http://www.example.com/test#Person">
    <rdfs:subClassOf rdf:resource="http://www.example.com/test#Mammal"/>
    <owl:disjointWith rdf:resource="http://www.example.com/test#Dog"/>
</owl:Class>

<owl:NamedIndividual rdf:about="http://www.example.com/test#Lulu">
    <rdf:type rdf:resource="http://www.example.com/test#Dog"/>
    <test:hasOwner rdf:resource="http://www.example.com/test#Smith"/>
</owl:NamedIndividual>

<owl:NamedIndividual rdf:about="http://www.example.com/test#Tank">
    <rdf:type rdf:resource="http://www.example.com/test#Dog"/>
    <test:hasOwner rdf:resource="http://www.example.com/test#Smith"/>
</owl:NamedIndividual>

<owl:NamedIndividual rdf:about="http://www.example.com/test#Nala">
    <rdf:type rdf:resource="http://www.example.com/test#Dog"/>
    <test:hasOwner rdf:resource="http://www.example.com/test#Smith"/>
</owl:NamedIndividual>

<owl:NamedIndividual rdf:about="http://www.example.com/test#Smith">
    <rdf:type rdf:resource="http://www.example.com/test#Person"/>
    <test:hasPet rdf:resource="http://www.example.com/test#Lulu"/>
    <test:hasPet rdf:resource="http://www.example.com/test#Nala"/>
    <test:hasPet rdf:resource="http://www.example.com/test#Tank"/>
</owl:NamedIndividual>

    <rdf:Description>
    <rdf:type rdf:resource="http://www.w3.org/2002/07/owl#AllDifferent"/>
        <owl:distinctMembers rdf:parseType="Collection">
            <rdf:Description rdf:about="http://www.example.com/test#Lulu"/>
            <rdf:Description rdf:about="http://www.example.com/test#Nala"/>
            <rdf:Description rdf:about="http://www.example.com/test#Smith"/>
            <rdf:Description rdf:about="http://www.example.com/test#Tank"/>
        </owl:distinctMembers>
    </rdf:Description>
</rdf:RDF>

我希望 Smith 被推断并成为 Animal_Lover.但是这段代码在 OWL(或 GraphDB)中不起作用.有什么问题?

I want Smith to be inferred and become Animal_Lover. But this code does not work in OWL (or GraphDB). What is the problem?

推荐答案

我认为您的要求属于 OWL DL，GraphDB 不支持.

I think what you ask for falls in OWL DL, which is not supported by GraphDB.

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