根据他们的价值与XmlSerializer的我怎么能忽略的属性 [英] How can I ignore properties according to their value with XmlSerializer

问题描述

我想用XmlSerializer的创造排除属性，如果他们有一个默认值的XML。这可能与XmlSerializer的还是我将不得不考虑的IXmlSerializable？

I'd like the XML created by XmlSerializer to exclude properties if they have a default value. Is this possible with XmlSerializer or am I going to have to look into IXmlSerializable?

例如，我可能有下面的类：

For example, I may have the following class:

public class PositionedObject
{
   public float X
   { get; set; }

   public float Y
   { get; set;}
}

我想告诉XmlSerializer的，当它系列化PositionedObject的实例，不包括X如果该值为0（与同为Y，如果是0）。

I'd like to tell the XmlSerializer that when it serializes an instance of PositionedObject, to not include X if the value is 0 (and same with Y if it is 0).

推荐答案

只是声明 ShouldSerializeX 返回true命名的方法，当值不为0：

Just declare a method named ShouldSerializeX that returns true when the value is not 0:

public bool ShouldSerializeX()
{
    return X != 0;
}

串行器会调用这个方法来决定属性是否应被序列化与否。

The serializer will call this method to decide whether the property should be serialized or not.

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