转换到字符字符串的ArrayList? [英] Converting ArrayList Strings of to Characters?

查看:107
本文介绍了转换到字符字符串的ArrayList?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

所以我得到user.I估算字符串的ArrayList也有字符的二维数组:私人的char [] []拼图;我需要帮助改变字符串的字符,所以我可以将它们输入二维数组谁能帮助??

 公共类WordSearchPuzzle
{
    私人的char [] []拼图;
    私人的ArrayList<串GT; puzzleWords;
    私人INT letterCount = 0;
    私人诠释gridDimensions;    公共WordSearchPuzzle(ArrayList的<串GT; userSpecifiedWords)
    {
        this.puzzleWords = userSpecifiedWords;    }    私人无效createPuzzleGrid()
    {
        INT I;
        对于(i = 0; I< puzzleWords.size();我++){
            letterCount = puzzleWords.size()+ letterCount;
        }
        gridDimensions = letterCount * 2;
        拼图=新的char [gridDimensions] [gridDimensions];
    }


解决方案

每个字符串更改为的 charArray

 为(字符串项:ArrayList的){
  item.toCharArray();
}

So I have an arrayList of Strings imputed by the user.I also have a 2d array of chars : private char[][] puzzle ; I need help changing the Strings to characters so I can enter them into the 2d array can anyone help??

public class WordSearchPuzzle
{
    private char[][] puzzle ;
    private ArrayList<String> puzzleWords ;
    private int letterCount = 0 ;
    private int gridDimensions;

    public WordSearchPuzzle(ArrayList<String> userSpecifiedWords)
    {
        this.puzzleWords = userSpecifiedWords ;

    }

    private void createPuzzleGrid()
    {
        int i;
        for(i = 0; i < puzzleWords.size() ; i++){
            letterCount = puzzleWords.size() + letterCount ;
        }
        gridDimensions = letterCount * 2;
        puzzle = new char[gridDimensions][gridDimensions] ;
    }

解决方案

Change each string to a charArray.

for(String item : ArrayList){
  item.toCharArray();
}

这篇关于转换到字符字符串的ArrayList?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆