字符串数组的 ArrayList [英] ArrayList of String Arrays

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本文介绍了字符串数组的 ArrayList的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想做这样的事情:

private ArrayList<String[]> addresses = new ArrayList<String[3]>();

这似乎不起作用.在数组中存储每个地址有 3 个字段的多个地址而不为其创建单独的类的最简单方法是什么?

This does not seem to work. Whats the easiest way of storing multiple addresses with 3 fields per address in an array without creating a separate class for it?

推荐答案

对 3 个字符串使用第二个 ArrayList,而不是原始数组.即
private List>地址 = 新的 ArrayList>();

Use a second ArrayList for the 3 strings, not a primitive array. Ie.
private List<List<String>> addresses = new ArrayList<List<String>>();

然后你可以:

ArrayList<String> singleAddress = new ArrayList<String>();
singleAddress.add("17 Fake Street");
singleAddress.add("Phoney town");
singleAddress.add("Makebelieveland");

addresses.add(singleAddress);

(我认为这里的类型擦除可能会发生一些奇怪的事情,但我认为这不重要)

(I think some strange things can happen with type erasure here, but I don't think it should matter here)

如果您一味地使用原始数组,则只需稍作改动即可使您的示例工作.正如其他答案中所解释的,数组的大小不能包含在声明中.如此变化:

If you're dead set on using a primitive array, only a minor change is required to get your example to work. As explained in other answers, the size of the array can not be included in the declaration. So changing:

private ArrayList<String[]> addresses = new ArrayList<String[3]>();

private ArrayList<String[]> addresses = new ArrayList<String[]>();

会起作用.

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