字符数组VS字符指针用C [英] Char array vs Char Pointer in C

问题描述

我试图理解C指针，但我现在困惑与以下内容：

I am trying to understand pointers in C but I am currently confused with the following:

char *p = "hello"

- 这是在字符数组一个字符指针指向，开始为H

- this is a char pointer pointing at the character array, starting at h

char p[] = "hello"

- 这是一个存储你好阵列

- this is an array that stores hello.

有什么区别时，我通过这两个变量进入此功能？

What is the difference when I pass both these variables into this function?

void printSomething(char *p)
{
    printf("p: %s",p);
}

我不明白它们是如何不同。

I do not understand how they are different.

推荐答案

的char * 和的char [] 是不同类型的，但它不会立即显现在所有情况下。这是因为阵列的衰变为指针的，也就是说，如果提供的类型的char [] 的前pression那里类型的一个的char * 预计，编译器阵列会自动转换成一个指向它的第一个元素。

char* and char[] are different types, but it's not immediately apparent in all cases. This is because arrays decay into pointers, meaning that if an expression of type char[] is provided where one of type char* is expected, the compiler automatically converts the array into a pointer to its first element.

您例如函数 printSomething 期望一个指针，所以如果你尝试到一个数组中传递给它这样的：

Your example function printSomething expects a pointer, so if you try to pass an array to it like this:

char s[10] = "hello";
printSomething(s);

这是你写了这个编译器pretends：

The compiler pretends that you wrote this:

char s[10] = "hello";
printSomething(&s[0]);

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