函数删除字符串/字符数组空间用C [英] Function to remove spaces from string/char array in C
问题描述
问题问
下面是我到目前为止有：
的#include＆LT;＆stdio.h中GT;
＃包括LT＆;＆string.h中GT;
StringMax的的#define 1000 / * Maximium输入尺寸为1000个字符* /字符* deblank（字符*输入）/ * deblank接受一个char []参数，并返回一个char [] * /
{
字符*输出=输入;
的for（int i = 0，J = 0; I＆LT; strlen的（输入）;我++，J ++）/ *评估每一个字符输入* /
{
如果（输入由[i]！=''）/ *如果该字符不是空格* /
输出[J] =输入[I] / *该字符复制到输出的char [] * /
其他
j--; / *如果它是一个空间，然后不会增加产出指数（J），下无空间将当前索引中输入* /
}
返回输出; / *返回输出的char []。不应该有空格* /
}
诠释主要（无效）{
字符输入[StringMax的];
终止的char [] =END \\ N的; / *哨兵值，退出程序* / 的printf（STRING DE-BLANKER \\ n）;
的printf（请输入一个字符串到1000字符\\ n方式＆gt;）;
与fgets（输入，StringMax的，标准输入）; / *读取多达从标准输入1000个字符* / 而（STRCMP（输入，终止）！= 0）/ *检查阙退出！ * /
{
输入[strlen的（输入） - 1] ='\\ 0';
的printf（你输入：\\％s \\的\\ n，输入）; / *打印原始输入* /
的printf（你的新字符串是：％S \\ n，deblank（输入））; / *打印从deblank（输入）输出应该没有空格... DE-空白！ * / 的printf（请输入一个字符串到1000字符\\ n方式＆gt;）;
与fgets（输入，StringMax的，标准输入）; / *读取多达从标准输入另一个1000个字符... ...将继续下去，直到END中输入* /
}
}
从输入删除空格之后您还没有NUL终止符终止它（ \\ 0 ），因为新的长度小于或等于原始字符串
在年底只需NUL，终止它的for循环：
的char * deblank（字符*输入）
{
INT I，J;
字符*输出=输入;
对于（i = 0，J = 0; I＆LT; strlen的（输入）;我++，J ++）
{
如果（输入由[i]！=''）
输出[J] =输入[I]
其他
j--;
}
输出[J] = 0;
返回输出;
}
The question asked here is very similar to what I am having a problem with. The difference is that I must pass an argument to a function that removes the spaces and returns the resulting string/char array. I got the code working to remove the spaces but for some reason I am left with trailing characters left over from the original array. I even tried strncpy but I was having lots of errors.
Here is what I have so far:
#include <stdio.h>
#include <string.h>
#define STRINGMAX 1000 /*Maximium input size is 1000 characters*/
char* deblank(char* input) /* deblank accepts a char[] argument and returns a char[] */
{
char *output=input;
for (int i = 0, j = 0; i<strlen(input); i++,j++) /* Evaluate each character in the input */
{
if (input[i]!=' ') /* If the character is not a space */
output[j]=input[i]; /* Copy that character to the output char[] */
else
j--; /* If it is a space then do not increment the output index (j), the next non-space will be entered at the current index */
}
return output; /* Return output char[]. Should have no spaces*/
}
int main(void) {
char input[STRINGMAX];
char terminate[] = "END\n"; /* Sentinal value to exit program */
printf("STRING DE-BLANKER\n");
printf("Please enter a string up to 1000 characters.\n> ");
fgets(input, STRINGMAX, stdin); /* Read up to 1000 characters from stdin */
while (strcmp(input, terminate) != 0) /* Check for que to exit! */
{
input[strlen(input) - 1] = '\0';
printf("You typed: \"%s\"\n",input); /* Prints the original input */
printf("Your new string is: %s\n", deblank(input)); /* Prints the output from deblank(input) should have no spaces... DE-BLANKED!!! */
printf("Please enter a string up to 1000 characters.\n> ");
fgets(input, STRINGMAX, stdin); /* Read up to another 1000 characters from stdin... will continue until 'END' is entered*/
}
}
After removing the white spaces from the input you have not terminated it with nul-terminator (\0) because the new length is less than or equal to the original string.
Just nul-terminate it at the of end your for loop:
char* deblank(char* input)
{
int i,j;
char *output=input;
for (i = 0, j = 0; i<strlen(input); i++,j++)
{
if (input[i]!=' ')
output[j]=input[i];
else
j--;
}
output[j]=0;
return output;
}
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