使用 os.walk 查找和打印我的文件的名称，但无法打开它们?路径名问题? [英] Using os.walk to find and print names of my files, but unable to open them? Path name issue?

问题描述

我的相关代码块如下:

path = "\\Users\\Harmless\\Documents\\untitled"
cellorder = []
cellcont = []
for roots, dirs, files, in os.walk(path):
    for file in natural_sort(files):
        if "Row" in file:
            cellorder.append(file)
            with open(file,'r') as txt:
                print txt.readlines
            #print "file = %s" % file

这将成功列出我想要打开的所有文件(如注释掉的那样)，但是当我尝试以与打印文件名相同的方式传入文件名以读取它时:

This would successfully list all the files I want to open (as commented out), but when I try to pass in the filename the same way it was printed in order to read it:

IOError: [Errno 2] No such file or directory: 'Row0Col0Heat.txt'

我该如何解决这个问题?我是否需要在每个文件名中引用整个路径名和字符串替代?如果是这样，为什么?有没有更好的方法来引用/利用路径?

How can I fix this? Do I need to reference the entire path name and string substitute in each filename? If so, why? Is there a better way to reference/utilize paths?

推荐答案

尝试使用文件的绝对路径，可以通过

Try using the absolute path of the file, you can get the absolute path by

abs_file_path = os.path.abspath(file)

既然你已经有了基本路径，你也可以使用:

since you already have the base path, you can also use:

abs_file_path = os.path.join(path, file)

希望能帮到你

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