我如何计数阵列重复项目的出现 [英] How do I count occurrence of duplicate items in array

问题描述

我要统计每个重复项发生在一个数组，只有独特/非重复项目的数组各自的出现结束了。

下面是我的code;但我并不在那里我要去错了！

 ＆LT; PHP
$阵列=阵列（12,43,66,21,56,43,43,78,78,100,43,43,43,21）;// $previous [值] [出现]为（$ ARR = 0; $改编＆LT;计数（$数组）; $ ARR ++）{    目前$ = $阵列[$ ARR];
    为（$ N = 0; $ N＆LT;计数（$previous）; $ n ++）{
        如果（！$电流= $previous [$ n]的[0]）{// 12不是43  -   -   -   - ＆GT;真正
            如果（$当前！= $previous [计数（$previous）] [0]）{
                $previous [$ N +] [0] = $电流;
                $previous [$ N +] [1] = $计数器++;
            }
        }其他{
            $previous [$ n]的[1] = $计数器++;
            未设置（$previous [计数（$previous）-1] [0]）;
            未设置（$previous [计数（$previous）-1] [1]）;
        }
    }
}
//期望值
回声号; BR＆GT;＆LT; BR＆GT;'; // 7'。.Count之间（$previous）'＆LT：非重复项目
的print_r（$previous）; //阵列（{12,1}，{21,2}，{43,6}，{66,1}，{56,1}，{78,2}，{ 100,1}）
？＆GT;
 

解决方案

array_count_values​​ ，享受： - ）

$阵列=阵列（12,43,66,21,56,43,43,78,78,100,43， 43,43,21）;
$瓦尔斯= array_count_values​​（$数组）;
回声号非重复的项目：.Count之间（$丘壑）。'＆LT; BR＆GT;＆LT; BR＆GT;';
的print_r（$瓦尔斯）;


结果：

否。非重复的项目：7
排列
（
    [12] =＆GT; 1
    [43] =＆GT; 6
    [66] =＆GT; 1
    [21] =＆GT; 2
    [56] =＆GT; 1
    [78] =＆GT; 2
    [100] =＆GT; 1
）


I would like to count the occurrence of each duplicate item in an array and end up with an array of only unique/non duplicate items with their respective occurrences.

Here is my code; BUT I don't where am going wrong!

<?php
$array = array(12,43,66,21,56,43,43,78,78,100,43,43,43,21);

//$previous[value][Occurrence]

for($arr = 0; $arr < count($array); $arr++){

    $current = $array[$arr];
    for($n = 0; $n < count($previous); $n++){
        if($current != $previous[$n][0]){// 12 is not 43 -----> TRUE
            if($current != $previous[count($previous)][0]){
                $previous[$n++][0] = $current;
                $previous[$n++][1] = $counter++;
            }
        }else{  
            $previous[$n][1] = $counter++;
            unset($previous[count($previous)-1][0]);
            unset($previous[count($previous)-1][1]);
        }   
    }
}
//EXPECTED VALUES
echo 'No. of NON Duplicate Items: '.count($previous).'<br><br>';// 7
print_r($previous);// array( {12,1} , {21,2} , {43,6} , {66,1} , {56,1} , {78,2} , {100,1})
?>    

解决方案

array_count_values, enjoy :-)

$array = array(12,43,66,21,56,43,43,78,78,100,43,43,43,21);
$vals = array_count_values($array);
echo 'No. of NON Duplicate Items: '.count($vals).'<br><br>';
print_r($vals);

Result:

No. of NON Duplicate Items: 7
Array
(
    [12] => 1
    [43] => 6
    [66] => 1
    [21] => 2
    [56] => 1
    [78] => 2
    [100] => 1
)

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