$ P $在bash阵列ppending所有项目的变量 [英] Prepending a variable to all items in a bash array

问题描述

CURRENTFILENAMES=( "$(ls $LOC -AFl | sed "1 d" |  grep "[^/]$" | awk '{ print $9 }')" )

我已经写了上面的code，但我期待它在一个for循环，这是我写的，因此不表现

I have written the above code, however it is not behaving as I expect it to in a for-loop, which I wrote as so

  for a in "$CURRENTFILENAMES"; do
      CURRENTFILEPATHS=( "${LOC}/${a}" )
  done

这我预计prePEND变量中的值 LOC 来都在 CURRENTFILENAMES 阵列，但它刚刚$ p $它ppended到数组的开头，我怎么能解决这个问题？

Which I expected to prepend the value in the variable LOC to all of the items in the CURRENTFILENAMES array, however it has just prepended it to the beginning of the array, how can I remedy this?

推荐答案

您需要使用 + = 运营商追加到一个数组：

You need to use += operator for appending into an array:

CURRENTFILEPATHS+=( "${LOC}/${a}" )

不过解析 LS 输出是不可取的，使用找到代替。

However parsing ls output is not advisable, use find instead.

编辑：有道运行这个循环：

CURRENTFILEPATHS=()
while IFS= read -d '' -r f; do
   CURRENTFILEPATHS+=( "$f" )
done < <(find "$LOC" -maxdepth 1 -type f -print0)

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