Pivot_longer 6 列到 3 列 [英] Pivot_longer 6 columns to 3 columns

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问题描述

我知道我的问题很简单,但我整个上午都在尝试,但我无法理解.

I know my question is simple but I've trying all morning and I can't get my head around it.

我有这个数据框:

  GeneID Gene.Symbol01    Ratio.2h   Ratio.6h  Ratio.10h  Ratio.24h  Pvalue_2h
 1    174           FUT -0.23618761 -0.3276162 -0.1366940 -4.4899131 0.49045105
  Pvalue_6h Pvalue_10h   Pvalue_24h
 1 0.06128851 0.59995612 0.0001798584

而且我需要对除 GeneID 和 GeneSymbol 之外的所有列进行 pivot_longer.生成的数据框应该有 3 个新列.一时间:2h、6h、10h和24h.然后还有两列包含比率值,另一列包含 pvalues.

And I need to pivot_longer all columns except GeneID and GeneSymbol. The resulting data frame should have 3 new columns. One with time: 2h, 6h, 10h, and 24h. Then two more columns with the ratio values and another one with the pvalues.

我知道这应该通过结合 names_to 和 names_pattern 来完成.我尝试了很多东西,但我无法做到.

I know this should be done with a combinametion of names_to and names_pattern. I have tried many things but I can't get it.

我尝试过的最后一件事是:

Last thing I have tried was this:

pivot_longer(cols = -c(GeneID, Gene.Symbol01),
             names_to = c("Time", ".value"),
             names_pattern = "_")

输入:

structure(list(GeneID = 174, Gene.Symbol01 = "FUT", Ratio.2h = -0.23618761, 
    Ratio.6h = -0.3276162, Ratio.10h = -0.136694, Ratio.24h = -4.4899131, 
    Pvalue_2h = 0.49045105, Pvalue_6h = 0.06128851, Pvalue_10h = 0.59995612, 
    Pvalue_24h = 0.0001798584), row.names = c(NA, -1L), class = c("tbl_df", 
"tbl", "data.frame"))

推荐答案

使用 tidyverse 您可能希望 pivot_longer Ratio.2h 中的所有变量> 到 Pvalue_24h,然后 separate 分成 2 列.

Using tidyverse you might want to pivot_longer all variable from Ratio.2h to Pvalue_24h, then separate it into 2 columns.

library(tidyverse)

DF %>% 
  pivot_longer(Ratio.2h:Pvalue_24h, names_to = "var") %>%
  separate(var, into = c("type", "time"), sep = "_|\\.")

# # A tibble: 8 x 5
#   GeneID Gene.Symbol01 type   time      value
#    <dbl> <chr>         <chr>  <chr>     <dbl>
# 1    174 FUT           Ratio  2h    -0.236   
# 2    174 FUT           Ratio  6h    -0.328   
# 3    174 FUT           Ratio  10h   -0.137   
# 4    174 FUT           Ratio  24h   -4.49    
# 5    174 FUT           Pvalue 2h     0.490   
# 6    174 FUT           Pvalue 6h     0.0613  
# 7    174 FUT           Pvalue 10h    0.600   
# 8    174 FUT           Pvalue 24h    0.000180

然后,使用 pivot_wider

DF %>% 
  pivot_longer(Ratio.2h:Pvalue_24h, names_to = "var") %>%
  separate(var, into = c("type", "time"), sep = "_|\\.") %>%
  pivot_wider(names_from = "type", values_from = "value")

# # A tibble: 4 x 5
#   GeneID Gene.Symbol01 time   Ratio   Pvalue
#    <dbl> <chr>         <chr>  <dbl>    <dbl>
# 1    174 FUT           2h    -0.236 0.490   
# 2    174 FUT           6h    -0.328 0.0613  
# 3    174 FUT           10h   -0.137 0.600   
# 4    174 FUT           24h   -4.49  0.000180

数据

DF <- tribble(~GeneID, ~Gene.Symbol01,  ~Ratio.2h,   ~Ratio.6h, ~Ratio.10h, ~Ratio.24h, ~Pvalue_2h,~Pvalue_6h, ~Pvalue_10h,   ~Pvalue_24h,
              174, "FUT", -0.23618761, -0.3276162, -0.1366940, -4.4899131, 0.49045105,0.06128851, 0.59995612, 0.0001798584)

这篇关于Pivot_longer 6 列到 3 列的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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