使用 ListLinePlot 的赛车圈速图 [英] Motorsport Lap Chart using ListLinePlot

问题描述

我正在尝试获取赛车圈位置表并绘制类似于此的圈数图表 http://www.fia.com/en-GB/sport/championships/f1/2010/bahrain/Pages/lap_chart.aspx.

I'm trying to take a table of motorsport lap positions and plot a lap chart similar to this http://www.fia.com/en-GB/sport/championships/f1/2010/bahrain/Pages/lap_chart.aspx.

每一行对应一圈，第一圈在第一行.车号按照它们通过起点/终点线的顺序在每一行中列出表格可能看起来像这样(4 车比赛，6 圈:

Each row corresponds to a lap, with the first lap in the first row. The car numbers are listed across each row in the order they pass the start/finish line The table may look like this (4-car race, 6 laps:

1 3 2 4
1 3 2 4
1 3 4 2
3 1 4 2
3 1 4 2
3 4 1 2

1 3 2 4
1 3 2 4
1 3 4 2
3 1 4 2
3 1 4 2
3 4 1 2

在上面的例子中，第一圈后的顺序是1、3、2、4，到6圈比赛结束时，3号车获胜，4号车第二，依此类推.

In the above example, the order was 1,3,2,4 after the first lap, and by the end of the 6-lap race, car 3 won, car 4 was in second, and so on.

很容易绘制错误，我是这样做的:

It's easy to plot this incorrectly, I did this:

ListLinePlot[Table[Position[data,x],{x,4}]]

这确实产生了一个圈数图，但它在底部有第 1 个位置，在顶部有第 4 个位置，我真正需要的是 y 轴来运行 4-3-2-1，所以第一个位置是顶.

This does produce a lap chart, but it has 1st position at the bottom and 4th position at the top, and what I really need is the y-axis to run 4-3-2-1 so 1st position is at the top.

如何反转 y 轴，使其从 1(顶部)运行到 n(底部)?

How can I reverse the y-axis so it runs from 1(top) to n(bottom)?

推荐答案

只需使用象限 4 来解决屏幕上的位置问题.

Just use Quadrant 4 to settle the position-on-screen problem.

这也适用于 DNF！(未完成的驱动程序).

This also works for DNF! (Drivers that did not finish).

第一名绘制在 y = -1 处，第二名绘制在 y = -2 处，依此类推.注意 y 如何在 {{lap_, y_} 中被 -y 替换:>{lap - 1, -y}} 下面.

First place is plotted at y = -1, second place is plotted at y = -2, etc. Note how y is replaced by -y in {{lap_, y_} :> {lap - 1, -y}} below.

lap 减 1，因为我包含了起始位置的数据(lap=0).

lap was decremented by 1 because I included data for the starting position (lap=zero).

小幅重写，以处理不同数量的车手和圈数，并重新格式化代码以提高易读性.- 巫师先生

A minor rewrite, to work with different numbers of drivers and laps, and reformat the code for increased legibility. - Mr.Wizard

data = 
  {{1, 3, 2, 4},
   {1, 3, 2, 4},
   {1, 3, 4, 2},
   {3, 1, 4, 2},
   {3, 1, 4, 2},
   {3, 4, 1, 2}};

{p, n} = {Max@data, Length@data};

ticks = {#, #} &@Array[{-#, #} &, p];
ticks[[All, 1, 2]] = {"Pole", "Winner"};

PrependTo[data, Range@p];  (* add starting position *)

ListLinePlot[
 Replace[
   Array[data~Position~# &, p],
   {lap_, y_} :> {lap - 1, -y},
   {2}
 ],
 Frame -> True,
 FrameLabel ->
  {"Laps Completed",
   "Starting Positions",
   "Laps Completed",
   "Final Positions"},
 GridLines -> {Range[0, n + 1], None},
 FrameTicks -> {ticks, {All, All}},
 PlotRange -> {Automatic, {-.7, -.3 - p}},
 PlotStyle -> Thickness[.01]
]

在这种情况下，1 号车(从杆位发车的那辆车)在完成最后两圈之前退出.请注意，3 号车自动前进了一个位置.

Here's the case where car #1 (the one that started in the Pole Position) dropped out before completing the final two laps. Notice that car #3 automatically advanced by one position.

这篇关于使用 ListLinePlot 的赛车圈速图的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！