int *p = &a 和 q = &a 有什么区别 [英] What's the difference between int *p = &a and q = &a

问题描述

学习者问题.我可以用两种不同的方式声明和初始化一个指针

Learner question. I can declare and initialize a pointer in two different way

int a = 10;
int *p = &a;

还有

int a = 10;
int *q;
q = &a;

我想知道两者有什么区别，在内存中是如何工作的?

I want to know what is the difference between two and how does it work in the memory?

推荐答案

这两个是一样的 :

int *p; // declaration
p = &a; // assignment

另一方面，您将两个步骤合二为一:

and in the other you are combining the two steps together into one:

int *p=&a; // declaration and assignment

如果您开启了一些编译器优化，编译器可能会将这两个步骤结合起来.

And if you have some compiler optimizations ON, the compiler might combine the two steps.

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