使用 PowerShell 获取大文件的前 n 个字符 [英] Get the first n characters of a large file with PowerShell

问题描述

我有一个巨大的 XML 文件 (0.5 GB)，没有换行符.我希望能够在不打开整个文件的情况下查看前 200 个字符.有没有办法用 PowerShell 做到这一点?

I've got a huge XML file (0.5 GB), with no line breaks. I want to be able to look at, say, the first 200 characters without opening the whole file. Is there a way to do this with PowerShell?

推荐答案

PowerShell Desktop (up to 5.1)

您可以像这样使用 Get-Content 在字节级别读取:

PowerShell Desktop (up to 5.1)

You can read at the byte level with Get-Content like so:

$bytes = Get-Content .\files.txt -Encoding byte -TotalCount 200
[System.Text.Encoding]::Unicode.GetString($bytes)

如果日志文件是 ASCII，您可以将其简化为:

If the log file is ASCII you can simplify this to:

[char[]](Get-Content .\files.txt -Encoding byte -TotalCount 200)

PowerShell Core 6.0 及更新版本

PowerShell Core 不支持 byte 编码.它已被 -AsByteStream 参数取代.

PowerShell Core 6.0 and newer

PowerShell Core doesn't support byte encoding. It's been replaced by -AsByteStream parameter.

$bytes = Get-Content .\file.txt -AsByteStream -TotalCount 200
[System.Text.Encoding]::Unicode.GetString($bytes)

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