R:如何显示一串单词的前n个字符 [英] R: how to display the first n characters from a string of words

问题描述

我有以下字符串:

 Getty <- "Four score and seven years ago our fathers brought forth on this continent a new nation, conceived in liberty, and dedicated to the proposition that all  men are created equal."

我想显示前 10 个字符.所以我首先将字符串拆分为单个字符:

I want to display the first 10 characters. So I began by splitting the string into individual characters:

 split <- strsplit(Getty, split="")
 split 

我得到了所有的单个字符作为这一点.然后我制作前 10 个字符的子字符串.

I get all the individual characters as this point. Then I make a substring of the first 10 characters.

 first.10 <- substr(split, start=1, stop=10)
 first.10

这是输出:

 "c(\"F\", \"o\""

我不明白为什么会打印出来?我以为它会打印出类似的东西:

I am not understanding why this prints out? I thought it would just print out something like:

 "F" "o" "u" "r" "s" 

有什么办法可以改变我的代码来打印上面的内容吗?

Is there a way I can alter my code to print what I have above?

谢谢大家！

推荐答案

其他答案并没有像您在示例中那样消除空格，因此我将添加以下内容:

The other answers didn't eliminate the spaces as you did in your example, so I'll add this:

strsplit(substr(gsub("\\s+", "", Getty), 1, 10), '')[[1]]
#[1] "F" "o" "u" "r" "s" "c" "o" "r" "e" "a"

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