使用 printf 格式在 C 中打印等宽列 [英] Print equal-width columns in C using printf formatting

问题描述

我想在 C 中使用 printf 打印列.我写了这个代码:

I would like to print columns using printf in C. I wrote this code:

#include <stdio.h>

void printme(char *txt1, char *txt2, char *txt3)
{
    printf("TXT1: %9s TXT2 %9s TXT3 %9s\n", txt1, txt2, txt3);
}


int main()
{
    printme("a","bbbbbbbeeeeebbbbb","e");
    printme("aaaaaaaa","bbbbbbbbbbbb","abcde");
    return 0;
}

它有效，但我有这样的输出:

It works but I have such output:

TXT1:         a TXT2 bbbbbbbeeeeebbbbb TXT3         e
TXT1:  aaaaaaaa TXT2 bbbbbbbbbbbb TXT3     abcde

所以列不是等宽的.基本上，我想这样做，无论我的论点中的文本有多长，我的函数都会始终打印出一个漂亮的格式化列.问题是:我该怎么做?

So the columns are not equal-width. Basicly, I would like to make it like this, that no matter how long is text in my argument, my function would ALWAYS print out a nice formatted columns. The question is: how can I do this?

说 nice 我的意思是无论我传递给打印函数多长的文本，它总是会打印出等宽的列，例如:

By saing nice I meant that no matter how long text I pass to my printing function, it will always print out equal-width columns, for example:

我的输出如下所示:

a         cd`           fg           ij  
a         cd             fg           ij  
a         cd             fg           ij  
ab         cd             fg           ij  
ab         cd             fg           i j   
ab         cd             fg           ij  
ab         cd             fg           ij  
ab         cde             fgh         ij  
ab         cde             fgh         ij  

我希望它看起来像这样(无论我的文本参数有多长):

I want it to look like this (no matter how long my text arguments will be):

a         cd`           fg           ij  
a         cd            fg           ij  
a         cd            fg           ij  
ab        cd            fg           ij  
ab        cd            fg           ij   
ab        cd            fg           ij  
ab        cd            fg           ij  
ab        cde           fgh          ij  
ab        cde           fgh          ij    

推荐答案

你可以找到txt1、txt2和txt3，然后格式化:

You can find the maximum length for txt1, txt2, and txt3, and then format it:

// compute the max string length of txt1 inputs in advance
int s1 = strlen(firstTxt1);
if (s1 < strlen(secondTxt1)
    s1 = strlen(secondTxt1);
...

printf("%.*s %.*s %.*s\n", s1, txt1, s2, txt2, s3, txt3);

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