如何使用purrr从嵌套列表中选择具有相同名称的元素? [英] How to select elements with the same name from nested list with purrr?

问题描述

require(purrr)

list <- list( 
  node = list(a = list(y = 1, t = 1), b = list(y = 1, t = 2)),
  node = list(a = list(y = 1, t = 3), b = list(y = 1, t = 4))) 

如何使用 purrr 选择所有t"值?

How to select all "t" values with purrr?

推荐答案

如果您知道要从哪个级别提取信息，您可以使用 modify_depth 来解决这个问题.

You can use modify_depth for this if you know what level you want to pull the information out of.

您想为嵌套列表提取 t，这是级别 2.

You want to pull t out for the nested lists, which is level 2.

modify_depth(list, 2, "t")

$node
$node$a
[1] 1

$node$b
[1] 2


$node
$node$a
[1] 3

$node$b
[1] 4

purrr modify 函数系列返回与输入类型相同的对象，因此您需要 unlist 以获取一个向量而不是一个列表.

The purrr modify family of functions returns an object of the same type as the input, so you'd need to unlist to get a vector instead of a list.

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