在 Pycharm 中使用 sys.stdin 从文件中读取 [英] Reading from a file with sys.stdin in Pycharm

问题描述

我正在尝试测试一个简单的代码，该代码使用 Pycharm 逐行读取文件.

I am trying to test a simple code that reads a file line-by-line with Pycharm.

for line in sys.stdin:
    name, _ = line.strip().split("\t")
    print name

我有我想输入的文件在同一个目录:lib.txt

I have the file I want to input in the same directory: lib.txt

如何使用输入文件在 Pycharm 中调试我的代码?

How can I debug my code in Pycharm with the input file?

推荐答案

您需要创建自定义运行配置，然后将您的文件作为参数添加到脚本参数"框中.请参阅 Pycharm 的在线帮助以获取分步说明指南.

You need to create a custom run configuration and then add your file as an argument in the "Script Parameters" box. See Pycharm's online help for a step-by-step guide.

但是，即使您这样做(正如您发现的那样)，您的问题也不会解决，因为您没有解析正确的命令行参数.

However, even if you do that (as you have discovered), your problem won't work since you aren't parsing the correct command line arguments.

您需要改为使用 argparse:

You need to instead use argparse:

import argparse

parser = argparse.ArgumentParser()
parser.add_argument("filename", help="The filename to be processed")
args = parser.parse_args()
if args.filename:
    with open(filename) as f:    
        for line in f:
            name, _ = line.strip().split('\t')
            print(name)

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