Pygame 矩形不动? [英] Pygame the rectangle is not moving?

问题描述

你好，我是 pygame 的新手.当我尝试向右或向左移动 rect 时.矩形不会从一个位置移动到另一个位置，而是向右或向左扩展/延伸.

为什么?

导入pygame、sys、timepygame.init()红色 = (255, 0, 0)gameDisplay = pygame.display.set_mode((800, 600))pygame.display.set_caption('MyGame')移动_x = 200移动_y = 200为真:对于 pygame.event.get() 中的事件:如果 event.type == pygame.QUIT:pygame.quit()放弃()系统退出()如果 event.type == pygame.KEYDOWN:如果 event.key == pygame.K_LEFT:移动_x -= 10如果 event.key == pygame.K_RIGHT:移动_x += 10# pygame.Rect.move(10, 10)# gameDisplay.fill(white, rect=[move_x, move_y, 10, 100])pygame.draw.rect(gameDisplay, red, [move_x, move_y, 10, 10])pygame.display.update()pygame.display.flip()

请看上图.按左右键后的样子.

解决方案

绘制前使用surface.fill.

我使用的 [0, 0, 0] 在 RGB 代码中是黑色的.你应该声明类似

BLACK = (0, 0, 0)

作为避免重复的常量.所以请改变它并像上面一样使用它.

导入pygame、sys、timepygame.init()红色 = (255, 0, 0)gameDisplay = pygame.display.set_mode((800, 600))pygame.display.set_caption('MyGame')移动_x = 200移动_y = 200为真:对于 pygame.event.get() 中的事件:如果 event.type == pygame.QUIT:pygame.quit()放弃()系统退出()如果 event.type == pygame.KEYDOWN:如果 event.key == pygame.K_LEFT:移动_x -= 10如果 event.key == pygame.K_RIGHT:移动_x += 10# pygame.Rect.move(10, 10)gameDisplay.fill([0,0,0]) # 添加的行.pygame.draw.rect(gameDisplay, red, [move_x, move_y, 10, 10])pygame.display.update()pygame.display.flip()

注意不要在 fill 方法之前画任何东西，它会被擦除，因为你用别的东西填满了屏幕.

我刚刚意识到你已经定义了red.如果您将其全部大写，则可能会更好.红色.因为它是 PEP-8 建议的全局常量.>

Hello I am new to pygame. When I am trying to move my rect right or left. The rectangle does not move from one position to other rather it expands/extends towards right or left.

Why?

import pygame, sys, time

pygame.init()
red = (255, 0, 0)
gameDisplay = pygame.display.set_mode((800, 600))
pygame.display.set_caption('MyGame')
move_x = 200
move_y = 200


while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()
            sys.exit()
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                move_x -= 10

            if event.key == pygame.K_RIGHT:
                move_x += 10
        # pygame.Rect.move(10, 10)
        # gameDisplay.fill(white, rect=[move_x, move_y, 10, 100])
    pygame.draw.rect(gameDisplay, red, [move_x, move_y, 10, 10])
    pygame.display.update()
    pygame.display.flip()

Please see the image above. How it looks like after pressing right or left keys.

解决方案

Use surface.fill before drawing.

The [0, 0, 0] I used is black in RGB codes. You should declare something like

BLACK = (0, 0, 0)

As a constant to avoid repetition. So please change that and use it like above.

import pygame, sys, time

pygame.init()
red = (255, 0, 0)
gameDisplay = pygame.display.set_mode((800, 600))
pygame.display.set_caption('MyGame')
move_x = 200
move_y = 200


while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()
            sys.exit()
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                move_x -= 10

            if event.key == pygame.K_RIGHT:
                move_x += 10
        # pygame.Rect.move(10, 10)
    gameDisplay.fill([0,0,0]) # The line added.
    pygame.draw.rect(gameDisplay, red, [move_x, move_y, 10, 10])
    pygame.display.update()
    pygame.display.flip()

Be careful not to draw anything before the fill method, it will be erased because you filled the screen with something else.

Edit: I just realized you already defined red. It is probably better if you declared it all caps. RED. Because it is a global constant as PEP-8 suggests.

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