pyqt中的启动画面 [英] Splash screen in pyqt

问题描述

我想修改我的代码以在显示登录对话框之前添加启动画面(大约 2 秒).我尝试了一些东西(改成评论)但不起作用.请告诉我如何修改我的代码.

I want to modify my code to add the splash screen before login dialog is shown(about 2 seconds) .i tried something(changed into comment )but not working .please show me how to modify my code.

  import sys
  from time import *
  from PyQt4 import QtGui,QtCore
  from loginD import *
  from mainwindow import Ui_MainWindow

 class Login(QtGui.QDialog):
 #A dialog with username and password lineedit
  def __init__(self,parent=None):
    QtGui.QDialog.__init__(self,parent)
    self.ui=Ui_LoginD()
    self.ui.setupUi(self)
    self.ui.PasswordLE.setEchoMode(QtGui.QLineEdit.Password)
    QtCore.QObject.connect(self.ui.LoginPB,QtCore.SIGNAL('clicked()'),
                           self.HandleLogin)
def HandleLogin(self):
    if  self.ui.PasswordLE.text()=="pass":
        self.accept()

    else:
        QtGui.QMessageBox.warning(
            self,'Error;','bad')

class Main_Window(QtGui.QMainWindow,):
#main window ui 
 def __init__(self,parent=None):
    QtGui.QWidget.__init__(self,parent)
    self.ui=Ui_MainWindow()
    self.ui.setupUi(self)



if __name__=='__main__':
 app=QtGui.QApplication(sys.argv)
 #splash_pix=QtGui.QPixmap('logo and typeface blue.jpg')
 #splash=QtGui.QSplashScreen(splash_pix,QtCore.Qt.WindowStaysOnTopHint)
 #splash.show()
 # app.processEvents()
#time.sleep(2)
if Login().exec_()==QtGui.QDialog.Accepted:
    window=Main_Window()
    window.show()
    sys.exit(app.exec_())

推荐答案

使用计时器启动登录程序:

Use a timer to start the login procedure:

if __name__ == '__main__':

    app = QtGui.QApplication(sys.argv)

    splash_pix = QtGui.QPixmap('logo and typeface blue.jpg')
    splash = QtGui.QSplashScreen(splash_pix, QtCore.Qt.WindowStaysOnTopHint)
    splash.show()

    def login():
        splash.close()
        if Login().exec_() == QtGui.QDialog.Accepted:
            global window
            window = Main_Window()
            window.show()
        else:
            app.quit()

    QtCore.QTimer.singleShot(2000, login)

    sys.exit(app.exec_())

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