为什么这个对象数组中的每个元素得到由过去的对象覆盖? [英] Why does each element in this array of objects get overwritten by the last object?
问题描述
我有以下的code:
public static void main(String[] args) {
Player players[] = new Player[2];
Scanner kb = new Scanner(System.in);
System.out.println("Enter Player 1's name");
players[0] = new Player(kb.nextLine());
System.out.println("Enter Player 2's name");
players[1] = new Player(kb.nextLine());
System.out.println("Welcome "+ players[0].getName() + " and " + players[1].getName());
}
其目的是创造一个新的选手对象并存储游戏者的姓名,同时保持在阵列中的所有对象。
It is meant to create a new player object and store the name of the player, while keeping all the objects in the array.
下面是玩家等级:
public class Player {
static String name;
public Player(String playerName) {
name = playerName;
}
public String getName(){
return name;
}
}
什么实际情况是,当我刚刚有1对象它的工作原理,但是当我有2个,阵列中的每个元素都是一样的第二位。当我有数组中3个对象,每个元件是一样的第三等
What actually happens is that it works when I just have 1 object, but when I have 2, each element in the array is the same as the second. When I have 3 objects in the array, each element is the same as the 3rd, etc.
我不知道为什么发生这种情况,或如何纠正它,而且它已经莫名其妙我小时:/
I'm not sure why this is happening, or how to correct it, and it's been baffling me for hours :/
推荐答案
由于静电场的启示。静跨对象实例使用。它们存储在一流水平。
Its because of the static field. Statics are used across object instances. They are stored at class level.
下面code将工作:
class Player
{
String name;
public Player(String playerName)
{
name = playerName;
}
public String getName()
{
return name;
}
}
这篇关于为什么这个对象数组中的每个元素得到由过去的对象覆盖?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!