为什么这个对象数组中的每个元素都被最后一个对象覆盖? [英] Why does each element in this array of objects get overwritten by the last object?

查看:35
本文介绍了为什么这个对象数组中的每个元素都被最后一个对象覆盖?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下代码:

public static void main(String[] args) {
  Player players[] = new Player[2];
  Scanner kb = new Scanner(System.in);
  System.out.println("Enter Player 1's name");
  players[0] = new Player(kb.nextLine());
  System.out.println("Enter Player 2's name");
  players[1] = new Player(kb.nextLine());
  System.out.println("Welcome "+ players[0].getName() + " and " + players[1].getName());    
}

它的目的是创建一个新的播放器对象并存储播放器的名称,同时保留数组中的所有对象.

It is meant to create a new player object and store the name of the player, while keeping all the objects in the array.

这是播放器类:

public class Player {
  static String name;
  public Player(String playerName) {
    name = playerName;
  }

  public String getName(){
    return name;
  } 
}

实际发生的是,当我只有 1 个对象时它可以工作,但是当我有 2 个时,数组中的每个元素都与第二个相同.当数组中有 3 个对象时,每个元素与第 3 个相同,依此类推

What actually happens is that it works when I just have 1 object, but when I have 2, each element in the array is the same as the second. When I have 3 objects in the array, each element is the same as the 3rd, etc.

我不确定为什么会发生这种情况,或者如何纠正它,这让我困惑了几个小时:/

I'm not sure why this is happening, or how to correct it, and it's been baffling me for hours :/

推荐答案

是因为静态字段.静态用于跨对象实例.它们存储在类级别.

Its because of the static field. Statics are used across object instances. They are stored at class level.

下面的代码可以工作:

class Player
{
    String name;

    public Player(String playerName)
    {
        name = playerName;
    }

    public String getName()
    {
        return name;
    }
}

这篇关于为什么这个对象数组中的每个元素都被最后一个对象覆盖?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
相关文章
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆