PyQt:如何连接 QComboBox 以使用参数运行 [英] PyQt: How to connect QComboBox to function with Arguments

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问题描述

QComboBox 使用以下语法连接到函数:

QComboBox is connected to a function using following syntax:

myComboBox.activated.connect(self.myFunction )

但我需要能够将参数从 ComboBox 发送到 myFunction().但如果我使用:

But I need to be able to send the arguments from ComboBox to myFunction(). But if I use:

myComboBox.activated.connect(self.myFunction(myArg1, myArg2 )

我得到了

TypeError: connect() slot argument should be a callable or a signal, not 'NoneType'

需要使用什么语法将 QComboBox 连接到能够接收从 Comobobox 发送的参数的函数?

What syntax needs to be used to connect a QComboBox to a function that is able to receive arguments sent from Comobobox?

这是导致 TypeError 的代码:

Here is the code resulting an TypeError:

connect() 槽参数应该是可调用的或信号,而不是 'NoneType'

from PyQt4 import QtCore, QtGui
import sys

class MyClass(object):
    def __init__(self, arg):
        super(MyClass, self).__init__()
        self.arg = arg        

class myWindow(QtGui.QWidget):
    def __init__(self, parent=None):
        super(myWindow, self).__init__(parent)

        self.comboBox = QtGui.QComboBox(self)
        self.comboBox.addItems([str(x) for x in range(3)])

        self.myObject=MyClass(id(self) )

        self.comboBox.activated.connect(self.myFunction(self.myObject, 'someArg'))

    def myFunction(self, arg1=None, arg2=None):
        print '\n\t myFunction(): ', type(arg1),type(arg2)

if __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)
    app.setApplicationName('myApp')
    dialog = myWindow()
    dialog.show()
    sys.exit(app.exec_())

推荐答案

在我发布问题后,Stachoverflow 建议了一个链接,其中解释了很多.答案如下:

After I posted a question Stachoverflow suggested a link which explained a lot. Here is the answer:

from PyQt4 import QtCore, QtGui

class MyClass(object):
    def __init__(self, arg):
        super(MyClass, self).__init__()
        self.arg = arg        

class myWindow(QtGui.QWidget):
    def __init__(self, parent=None):
        super(myWindow, self).__init__(parent)

        self.comboBox = QtGui.QComboBox(self)
        self.comboBox.addItems([str(x) for x in range(3)])

        self.myObject=MyClass(id(self) )

        slotLambda = lambda: self.indexChanged_lambda(self.myObject)
        self.comboBox.currentIndexChanged.connect(slotLambda)

    @QtCore.pyqtSlot(str)
    def indexChanged_lambda(self, string):
        print 'lambda:', type(string), string

if __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)
    app.setApplicationName('myApp')
    dialog = myWindow()
    dialog.show()
    sys.exit(app.exec_())

这篇关于PyQt:如何连接 QComboBox 以使用参数运行的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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