如何在 PyQt 中发送 UI 事件? [英] How to send UI events in PyQt?

问题描述

我想在我的程序中自动化 UI 操作:它可以显示菜单、打开另一个表单等.我在我的 python 应用程序中使用 .py 文件和 .ui 文件.我该怎么做?

I want to automate UI actions in my program: it can be show a menu, open another form, etc. I'm using .py files and .ui files in my python app. How can i do this?

推荐答案

几乎所有的 GUI 框架都有一个事件的概念，它通常由用户操作(按钮单击、窗口拖动等)生成并发送到您的处理程序.

Almost all GUI frameworks have a notion of an event, which are typically generated by user actions (button clicking, window dragging, etc.) and send to your handlers.

但事件通常也可以直接发送到事件循环.就您而言，我假设您使用的是 Digia 的 PyQt 和 Qt 工具包.

But event can usually also be sent directly to the event loop. In your case, I'm assuming you're using PyQt and Qt toolkit from Digia.

QCoreApplication.sendEvent 的 PyQt 文档a> 看起来是个不错的起点:

The PyQt docs for QCoreApplication.sendEvent look like a good place to start:

bool QCoreApplication.sendEvent(QObject 接收器，QEvent 事件)

使用notify() 函数将事件事件直接发送到接收者接收者.返回从事件处理程序返回的值.

Sends event event directly to receiver receiver, using the notify() function. Returns the value that was returned from the event handler.

事件发送后不会删除事件.正常的做法是在栈上创建事件，例如:

The event is not deleted when the event has been sent. The normal approach is to create the event on the stack, for example:

QMouseEvent event(QEvent.MouseButtonPress, pos, 0, 0, 0);
QApplication.sendEvent(mainWindow, &event);

另见 postEvent() 和 notify().

See also postEvent() and notify().

不要忽略对 postEvent 和 notify 的另见.

Don't ignore the see-alsos to postEvent and notify.

更多信息也将在 Digia 的 postEvent Qt 文档

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