'str' 对象没有属性 'decode'.Python 3 错误? [英] 'str' object has no attribute 'decode'. Python 3 error?
问题描述
这是我的代码:
import imaplib
from email.parser import HeaderParser
conn = imaplib.IMAP4_SSL('imap.gmail.com')
conn.login('example@gmail.com', 'password')
conn.select()
conn.search(None, 'ALL')
data = conn.fetch('1', '(BODY[HEADER])')
header_data = data[1][0][1].decode('utf-8')
此时我收到错误消息
AttributeError: 'str' object has no attribute 'decode'
Python 3 没有解码了,对吗?我怎样才能解决这个问题?
Python 3 doesn't have decode anymore, am I right? how can I fix this?
此外,在:
data = conn.fetch('1', '(BODY[HEADER])')
我只选择第一封电子邮件.如何全选?
I am selecting only the 1st email. How do I select all?
推荐答案
您正在尝试解码一个已经解码的对象.你有一个 str
,就不需要再从 UTF-8 解码了.
You are trying to decode an object that is already decoded. You have a str
, there is no need to decode from UTF-8 anymore.
只需删除 .decode('utf-8')
部分:
header_data = data[1][0][1]
至于您的 fetch()
调用,您明确要求仅获取第一条消息.如果要检索更多消息,请使用范围.请参阅文档:
As for your fetch()
call, you are explicitly asking for just the first message. Use a range if you want to retrieve more messages. See the documentation:
下面命令的 message_set 选项是一个字符串,指定要对其执行的一个或多个消息.它可能是一个简单的消息号('1'
)、一个消息号范围('2:4'
)或一组由逗号 ('1:3,6:9'
).一个范围可以包含一个星号来表示一个无限的上限 ('3:*'
).
The message_set options to commands below is a string specifying one or more messages to be acted upon. It may be a simple message number (
'1'
), a range of message numbers ('2:4'
), or a group of non-contiguous ranges separated by commas ('1:3,6:9'
). A range can contain an asterisk to indicate an infinite upper bound ('3:*'
).
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