设置一个数组的所有值最快的方法？ [英] Fastest way to set all values of an array?

问题描述

我有一个的char [] ，我想每一个指标的值设置为相同的字符值。结果
还有就是明显的方式做到这一点（迭代）：

I have a char [], and I want to set the value of every index to the same char value.
There is the obvious way to do it (iteration):

  char f = '+';
  char [] c = new char [50];
  for(int i = 0; i < c.length; i++){
      c[i] = f;
  }

但我在想，如果有，将绕过需要遍历的方式，我可以利用 System.arraycopy 或等值的东西。有没有办法做到这一点？

But I was wondering if there's a way that I can utilize System.arraycopy or something equivalent that would bypass the need to iterate. Is there a way to do that?

编辑：
从 Arrays.java

public static void fill(char[] a, int fromIndex, int toIndex, char val) {
        rangeCheck(a.length, fromIndex, toIndex);
        for (int i = fromIndex; i < toIndex; i++)
            a[i] = val;
    }

这是完全一样的过程，这表明，有可能不是一个更好的方式来做到这一点。
结果+1大家谁建议填写反正 - 你是正确的，感谢您

This is exactly the same process, which shows that there might not be a better way to do this.
+1 to everyone who suggested fill anyway - you're all correct and thank you.

推荐答案

尝试 Arrays.fill（C，F）：<一href=\"http://docs.oracle.com/javase/7/docs/api/java/util/Arrays.html#fill%28char%5B%5D,%20char%29\">Arrays javadoc的

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