在 Python 中通过套接字发送文件 [英] Send a file through sockets in Python

问题描述

我正在尝试用 python 编写一个实现套接字的程序.每个客户端发送一个 PDF 文件，服务器接收它并且将标题更改为file_(number).pdf".(例如:file_1.pdf).出现的问题是只有客户端才能成功发送文件.当第二个客户端尝试发送文件时，程序崩溃.我做错了什么，如何解决我的代码以允许 N 个客户端(N <20)连接到服务器并传输文件?

I'm trying to make a program in python that implements sockets. Each client sends a PDF file and the server receives it and the title is changed to "file_(number).pdf" (e.g.: file_1.pdf). The problem presented is that only a client can send a file successfully. When a second client tries to send the file, the program crashes. What am I doing wrong and how can I solve my code to allow N clients (with N < 20) to connect to the server and transfer files?

这是服务器代码:

import socket
import sys
s = socket.socket()
s.bind(("localhost",9999))
s.listen(10) # Accepts up to 10 incoming connections..
sc, address = s.accept()

print address
i=1
f = open('file_'+ str(i)+".pdf",'wb') # Open in binary
i=i+1
while (True):

    # We receive and write to the file.
    l = sc.recv(1024)
    while (l):
        f.write(l)
        l = sc.recv(1024)
f.close()

sc.close()
s.close()

这是客户端代码:

import socket
import sys

s = socket.socket()
s.connect(("localhost",9999))
f = open ("libroR.pdf", "rb")
l = f.read(1024)
while (l):
    s.send(l)
    l = f.read(1024)
s.close()

为了简化我的代码，我总是使用文件名为libroR.pdf"的书，但在完整代码中，它是由 GUI 选择的.

To simplify my code, I always use a book with file name "libroR.pdf", but in the full code it is chosen by a GUI.

推荐答案

你必须把所有的代码从 sc, address = s.accept() 到 sc.close() 进入另一个循环，或者服务器在收到第一个文件后简单地终止.它没有崩溃，脚本刚刚完成.

You must put all the code from sc, address = s.accept() upto sc.close() into another loop or the server simply terminates after receiving the first file. It doesn't crash, the script is just finished.

这是修改后的代码:

import socket
import sys
s = socket.socket()
s.bind(("localhost",9999))
s.listen(10) # Accepts up to 10 connections.

while True:
    sc, address = s.accept()

    print address
    i=1
    f = open('file_'+ str(i)+".pdf",'wb') #open in binary
    i=i+1
    while (True):       
    # receive data and write it to file
        l = sc.recv(1024)
        while (l):
                f.write(l)
                l = sc.recv(1024)
    f.close()


    sc.close()

s.close()

请注意，s.listen(10) 的意思是将最大接受率设置为 10 个连接"，而不是在 10 个连接后停止".

Note that s.listen(10) means "set maximum accept rate to 10 connections", not "stop after 10 connections".

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