通过套接字发送字符串(python) [英] Sending string via socket (python)

问题描述

我有两个脚本，Server.py和Client.py. 我有两个目标:

I have two scripts, Server.py and Client.py. I have two objectives in mind:

1. 能够一次又一次地从客户端向服务器发送数据.
2. 能够将数据从服务器发送到客户端.

这是我的Server.py:

here is my Server.py :

import socket

serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = "192.168.1.3"
port = 8000
print (host)
print (port)
serversocket.bind((host, port))

serversocket.listen(5)
print ('server started and listening')
while 1:
    (clientsocket, address) = serversocket.accept()
    print ("connection found!")
    data = clientsocket.recv(1024).decode()
    print (data)
    r='REceieve'
    clientsocket.send(r.encode())

这是我的客户:

#! /usr/bin/python3

import socket

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host ="192.168.1.3"
port =8000
s.connect((host,port))

def ts(str):
   s.send('e'.encode()) 
   data = ''
   data = s.recv(1024).decode()
   print (data)

while 2:
   r = input('enter')
   ts(s)

s.close ()

该函数首次运行("e"进入服务器，我返回返回消息)，但是如何使它一遍又一遍地发生(类似于聊天应用程序)? 该问题在第一次之后开始.消息不会在第一次之后发送. 我究竟做错了什么? 我是python的新手，所以请详细说明一下，如果可以的话，请提供整个内容的源代码.

The function works for the first time ('e' goes to the server and I get return message back), but how do I make it happen over and over again (something like a chat application) ? The problem starts after the first time. The messages don't go after the first time. what am I doing wrong? I am new with python, so please be a little elaborate, and if you can, please give the source code of the whole thing.

推荐答案

import socket
from threading import *

serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = "192.168.1.3"
port = 8000
print (host)
print (port)
serversocket.bind((host, port))

class client(Thread):
    def __init__(self, socket, address):
        Thread.__init__(self)
        self.sock = socket
        self.addr = address
        self.start()

    def run(self):
        while 1:
            print('Client sent:', self.sock.recv(1024).decode())
            self.sock.send(b'Oi you sent something to me')

serversocket.listen(5)
print ('server started and listening')
while 1:
    clientsocket, address = serversocket.accept()
    client(clientsocket, address)

这是一个非常简单的设计，可以解决您的问题. 首先，您需要在进入while 1循环之前接受客户端(服务器端)，因为在每个循环中您都接受一个新的客户端，或者按照我的描述，您将客户端扔到一个单独的线程中，从现在开始自己处理.

This is a very VERY simple design for how you could solve it. First of all, you need to either accept the client (server side) before going into your while 1 loop because in every loop you accept a new client, or you do as i describe, you toss the client into a separate thread which you handle on his own from now on.

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