使用GapSocket将字符串发送到tcp套接字 [英] Send string to a tcp socket using GapSocket
问题描述
我尝试使用 GapSocket 建立套接字连接并且将一些数据（字符串）从PhoneGap发送到端口8888打开的计算机的tcp套接字。我包含了所有的依赖关系：
I am trying to establish a socket connection using GapSocket and send some data (strings) to a tcp socket from an PhoneGap to a computer with port 8888 open. I have included all dependencies:
- 从 cocoaasyncsocket
- GapSocketCommand.m和GapSocketCommand.h都来自GapSocket
- 包含GapSocket.js并在www文件夹下的index.html中引用了js文件。
以下是我的index.html文件：
Following is my index.html file:
<!DOCTYPE html>
<html>
<head>
<title>Socket Test</title>
<script type="text/javascript" charset="utf-8" src="phonegap-1.1.0.js"></script>
<script type="text/javascript">
document.addEventListener("deviceready", function(){
var mySocket = new GapSocket(127.0.0.1, 8888);
mySocket.onopen = function(){ alert("Socket opened."); };
mySocket.send("some data here");
}, false);
</script>
</head>
<body>
</body>
t抛出任何依赖性错误，并能够在iOS模拟器上运行。在我运行之前，我打开端口8888在127.0.0.1（模拟器运行的机器）使用：
It compiles okay and doesn't throw any dependency error and able to run on iOS Simulator. Before I run, I opened port 8888 on 127.0.0.1 (the machine that the Simulator runs) using:
nc -l 127.0.0.1 8888
nc -l 127.0.0.1 8888
我可以使用telnet连接开放端口和发送数据：
I can connect the open port and send data by using telnet:
telnet 127.0.0.1 8888
telnet 127.0.0.1 8888
发送以下数据：
eddy-2:~ eddy$ telnet 127.0.0.1 8888
Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
test
test
回到iOS模拟器，发送任何东西，我不知道我是否正确的方式初始化套接字（我是新的PhoneGap和Xcode）。我按照自述的步骤，但它不提供太多的上下文。
Coming back to the iOS Simulator, it runs but doesn't send anything out and I am not sure if I am doing the correct way of initializing the socket (I am new to both PhoneGap and Xcode). I followed steps on the readme but it doesn't provide much context.
推荐答案
您需要在cordova.plist插件与GapSocketCommand字符串和值
you need to include an entry in cordova.plist plugin with GapSocketCommand string and value
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