在给定字符的第 n 次出现处拆分字符串 [英] Split string at nth occurrence of a given character

问题描述

在给定定界符出现第 n 次后，是否有一种 Python 方式来分割字符串?

Is there a Python-way to split a string after the nth occurrence of a given delimiter?

给定一个字符串:

'20_231_myString_234'

它应该被拆分为(在第二次出现后，分隔符为_"):

It should be split into (with the delimiter being '_', after its second occurrence):

['20_231', 'myString_234']

或者是唯一的方法来完成计数、拆分和加入?

Or is the only way to accomplish this to count, split and join?

推荐答案

>>> n = 2
>>> groups = text.split('_')
>>> '_'.join(groups[:n]), '_'.join(groups[n:])
('20_231', 'myString_234')

似乎这是最易读的方式，替代的是正则表达式)

Seems like this is the most readable way, the alternative is regex)

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