代码块的 Python 正则表达式? [英] Python regex for blocks of code?

问题描述

如何创建一个正则表达式，它可以匹配一行的开头以及以下所有以 tab 开头的行?例如

不是关键字；不是这条线；关键字和随机文本；这条线；这条线；和这条线；不是关键字；

我希望能够匹配从 '^keyword' 到 'and this line ;'

谢谢.

编辑.我正在尝试为不需要的节点删除 Maya 的 MEL 代码.实际代码如下所示，多行 setAttr 和制表符缩进.

createNode mentalrayOptions ...........设置属性………………

我将整个文本加载到 1 个变量中

 with open( 'path/to/file', 'r') as content_file:内容 = content_file.read()

我尝试的正则表达式似乎正确地找到了起点，但我无法正确地获得终点.它要么匹配 1 行，根本不匹配任何内容，要么一直匹配到文件末尾.

match = re.search( r'(^createNode mentalrayOptions)(.*\n)(^\t)' ,content, flags=re.DOTALL)

解决方案

你可以这样使用:

^keyword.*(?:\n^\t.*)*

标志:

• m 用于 mutiline，所以 ^ 有效.
• not s 所以 . 不匹配换行符.

说明:

• ^keyword - 以 keyword
开头的行
• .* - 匹配到行尾
• (?:\n^\t.*)* - 每一个都匹配以制表符开头的另一行.请注意，我们需要匹配换行符，因此请注意是否有其他行分隔符.

工作示例:http://www.regex101.com/r/jP8yH0>

当然，如果您尝试匹配真实代码块，这可能会很快失败 - 例如通过注释或字符串文字.

How do I created a regex that can match a start of a line and also all the following lines starting with tab? For example

not keyword ;
    not this line ;
keyword and random text ;
    this line ;
    this line ;
    and this line ;
not keyword ;

I want to be able to match starting from '^keyword' to 'and this line ;'

Thank you.

edit. I'm trying to remove Maya's MEL code for the node I don't need. The actual code looks like this, with multiple lines of setAttr with tab indent.

createNode mentalrayOptions ......... ;
    setAttr .............. ; 

I load the entire text into 1 variable with

with open( 'path/to/file', 'r') as content_file:
    content = content_file.read()

the regex I tried seem to find the starting point correctly but I can't get the end point correctly. It either matches 1 line, not matching anything at all or matches all the way to the end of file.

match = re.search( r'(^createNode mentalrayOptions)(.*\n)(^\t)' ,content, flags=re.DOTALL)

解决方案

You could use something like this:

^keyword.*(?:\n^\t.*)*

Flags:

• m for mutiline, so ^ works.
• not s so . does not match new-lines.

Explanation:

• ^keyword - Start of the line with keyword
• .* - match until the end of the line
• (?:\n^\t.*)* - each of these matches another line that begins with a tab. Note that we hat to match the new-line, so take care if you have other line separators.

Working example: http://www.regex101.com/r/jP8yH0

Naturally, if you are trying to match real blocks of code, this can fail quickly - for example by comments or string literals.

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