Python:在没有 for 循环的情况下将值附加到列表 [英] Python: Append values to list without for-loop

问题描述

如何在不使用 for 循环的情况下将值附加到列表中?

我想避免在这段代码中使用循环:

count = []对于范围内的 i (0, 6):打印将 %d 添加到列表中."％ 一世count.append(i)

结果必须是:

count = [0, 1, 2, 3, 4, 5]

我尝试了不同的方法，但我无法做到.

解决方案

范围:

因为 range 返回一个列表，你可以简单地做

<预><代码>>>>计数 = 范围(0,6)>>>数数[0, 1, 2, 3, 4, 5]

避免循环的其他方法(docs):

扩展:

<预><代码>>>>计数 = [1,2,3]>>>count.extend([4,5,6])>>>数数[1, 2, 3, 4, 5, 6]

相当于count[len(count):len(count)] = [4,5,6],

和功能与count += [4,5,6]相同.

切片:

<预><代码>>>>计数 = [1,2,3,4,5,6]>>>计数[2:3] = [7,8,9,10,11,12]>>>数数[1, 2, 7, 8, 9, 10, 11, 12, 4, 5, 6]

(从 2 到 3 的 count 切片被右边的可迭代内容替换)

How can I append values to a list without using the for-loop?

I want to avoid using the loop in this fragment of code:

count = []
for i in range(0, 6):
    print "Adding %d to the list." % i
    count.append(i)

The result must be:

count = [0, 1, 2, 3, 4, 5]

I tried different ways, but I can't manage to do it.

解决方案

Range:

since range returns a list you can simply do

>>> count = range(0,6)
>>> count
[0, 1, 2, 3, 4, 5]

Other ways to avoid loops (docs):

Extend:

>>> count = [1,2,3]
>>> count.extend([4,5,6])
>>> count
[1, 2, 3, 4, 5, 6]

Which is equivalent to count[len(count):len(count)] = [4,5,6],

and functionally the same as count += [4,5,6].

Slice:

>>> count = [1,2,3,4,5,6]
>>> count[2:3] = [7,8,9,10,11,12]
>>> count
[1, 2, 7, 8, 9, 10, 11, 12, 4, 5, 6]

(slice of count from 2 to 3 is replaced by the contents of the iterable to the right)

这篇关于Python:在没有 for 循环的情况下将值附加到列表的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！