如何在 Python 2 中取大数的平方根? [英] How to take square root of large numbers in Python 2?

问题描述

我正在尝试检查一个大数是否是完全平方数.这是我代码的相应部分:

I am trying to check if a large number is a perfect square. Here is the corresponding part of my code:

x = long(raw_input())
a = sqrt(5 * x ** 2 + 4)
b = sqrt(5 * x **2 - 4)
if long(a) == a or long(b) == b:
    print "YES"
else:
    print "NO" 

但是，当 x 变得太大时，我会收到此错误:

However, when x becomes too large, I get this error:

    a = sqrt(5 * x ** 2 + 4)
OverflowError: long int too large to convert to float

有人可以告诉我解决方法吗?

Can anybody tell me a workaround for this?

推荐答案

使用 十进制模块 取大数的平方根.

Use the decimal module to take the square root of large numbers.

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