正则表达式删除python中的特定单词 [英] Regex to remove specific words in python

问题描述

我想在 python 中使用正则表达式进行一些操作.

I want to do the some manipulation using regex in python.

所以输入是 +1223,+12_remove_me,+222,+2223_remove_me和输出应该是 +1223,+222

So input is +1223,+12_remove_me,+222,+2223_remove_me and output should be +1223,+222

输出应该只包含逗号分隔的单词，不包含 _remove_me 并且每个单词之间只有一个逗号.

Output should only contain comma seperated words which don't contain _remove_me and only one comma between each word.

注意:我尝试过的正则表达式 \+([0-9|+]*)_ , \+([0-9|+]*) 和其他一些我没有得到所需输出的组合.

Note: REGEX which I tried \+([0-9|+]*)_ , \+([0-9|+]*) and some other combination using which I did not get required output.

注意 2 我不能使用循环，需要在没有循环的情况下只使用正则表达式.

Note 2 I can't use loop, need to do that without loop with regex only.

推荐答案

您的正则表达式似乎不完整，但您走对了.请注意，字符类中的管道符号被视为文字，您的 [0-9|+] 匹配数字或 | 或 + 符号.

Your regex seems incomplete, but you were on the right track. Note that a pipe symbol inside a character class is treated as a literal and your [0-9|+] matches a digit or a | or a + symbols.

你可以使用

,?\+\d+_[^,]+

查看正则表达式演示

说明:

• ,? - 可选的,(如果单词"在字符串的开头，则应该是可选的)
• \+ - 文字 +
• \d+ - 1+ 个数字
• _ - 文字下划线
• [^,]+ - 除了 ,
之外的 1+ 个字符

• ,? - optional , (if the "word" is at the beginning of the string, it should be optional)
• \+ - a literal +
• \d+ - 1+ digits
• _ - a literal underscore
• [^,]+ - 1+ characters other than ,

Python 演示:

import re
p = re.compile(r',?\+\d+_[^,]+')
test_str = "+1223,+12_remove_me,+222,+2223_remove_me"
result = p.sub("", test_str)
print(result)
# => +1223,+222

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