Bash正则表达式在句子中查找特定单词 [英] Bash regex finding particular words in a sentence

问题描述

我有一个这样的句子:

"The dog jumped over the moon because he likes jumping"

我想找到所有与 jump.* 匹配的单词，即 jumped 和 jumping.我该怎么做?

And I want to find all words that match jump.*, i.e. jumped and jumping. How can I do this?

目前我将句子放在一个变量中，$sentence.我知道我想测试的匹配词，例如$test 是 jump.

Currently I have the sentence in a variable, $sentence. And I know the match word that I want to test against, e.g. $test is jump.

谢谢

推荐答案

试试这个正则表达式:

/\bjump.*?\b/

请参阅此处.\b 匹配单词边界和 jump.*? 之间以 jump 开头的所有内容.

See here. \b matches word boundaries and jump.*? everything between that starts with jump.

在 bash 中，您可以将它与 grep 一起使用:

In bash you can use it with grep:

echo $sentence | grep -oP "\b$test.*?\b"

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