Python 2.7 缩进错误 [英] Python 2.7 Indentation error

问题描述

我是 Python 新手，在以下代码中出现缩进错误:

Hi I am new to Python having an indentation error in the following code:

print "------------------------- Basics Arithamatic Calculator-------------------------"

int_num_one=input('Enter First Num: ')
int_num_two=input('Enter Second Num: ')

list_options={"+", "-", "/", "*"}

print "Which operation you want to perform *, -, +, / ?"
char_selected_option=raw_input()
print "Operation selected is %r" % (char_selected_option)

for char_symbol in list_options:
    print "Char symbol is %r" % (char_symbol)
bool_operation_Not_Found=True
if char_symbol==char_selected_option:
    int_result=str(int_num_one) + char_selected_option + str(int_num_two)
    print int_result
    print "%d %s %d = %d" % (int_num_one, char_selected_option, int_num_two, eval(int_result))
    bool_operation_Not_Found=False
break
if bool_operation_Not_Found:
print "Invalid Input"

推荐答案

看起来 for 循环内部"的代码没有正确缩进，这应该可以工作.

It looks like the code 'inside' the for loop was not indented correctly, this should work.

for char_symbol in list_options:
    print "Char symbol is %r" % (char_symbol)
    bool_operation_Not_Found=True
    if char_symbol==char_selected_option:
        int_result=str(int_num_one) + char_selected_option + str(int_num_two)
        print int_result
        print "%d %s %d = %d" % (int_num_one, char_selected_option, int_num_two, eval(int_result))
        bool_operation_Not_Found=False
        break
if bool_operation_Not_Found:
    print "Invalid Input"

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