根据其位置更改字符?蟒蛇 2.7 [英] Change character based off of its position? Python 2.7

问题描述

我有一个未知长度的字符串，包含字符 a-z A-Z 0-9.我需要使用字典从左到右更改每个字符的位置.

I have a string on unknown length, contain the characters a-z A-Z 0-9. I need to change each character using their position from Left to Right using a dictionary.

示例:

string = "aaaaaaaa"
def shift_char(text):
    for i in len(text):
        # Do Something for each character
    return output
print shift_char(string)
'adktivep'

推荐答案

在 Mark Tolonen 的帮助下这篇文章，我能来提出解决方案.下面的例子只使用了 4 个字典，而我打算做更多:

With the help of Mark Tolonen in this post, I was able to come up with a solution. The following example only uses 4 dictionaries, while i intend to do more:

# Input String
string = "ttttttttttttttttttttttttttttttt"

# Defining dictionarys for 0-4
dicnums = [{"0":"n","1":"Q","2":"k","3":"W","4":"F","5":"g","6":"9","7":"e","8":"v","9":"3","a":"r","b":"T","c":"c","d":"o","e":"b","f":"y","g":"2","h":"A","i":"i","j":"p","k":"1","l":"P","m":"w","n":"x","o":"s","p":"Y","q":"h","r":"G","s":"7","t":"S","u":"6","v":"K","w":"Z","x":"M","y":"C","z":"J","A":"u","B":"f","C":"j","D":"E","E":"a","F":"H","G":"O","H":"N","I":"l","J":"U","K":"I","L":"V","M":"m","N":"5","O":"R","P":"4","Q":"z","R":"L","S":"0","T":"q","U":"D","V":"8","W":"B","X":"X","Y":"d","Z":"t"}, {"0":"q","1":"6","2":"W","3":"4","4":"J","5":"u","6":"n","7":"T","8":"I","9":"O","a":"V","b":"3","c":"Z","d":"s","e":"R","f":"E","g":"G","h":"P","i":"5","j":"l","k":"e","l":"m","m":"F","n":"t","o":"8","p":"K","q":"L","r":"Y","s":"M","t":"D","u":"j","v":"z","w":"H","x":"g","y":"9","z":"f","A":"0","B":"p","C":"o","D":"d","E":"X","F":"S","G":"k","H":"1","I":"Q","J":"C","K":"U","L":"i","M":"r","N":"w","O":"y","P":"B","Q":"2","R":"x","S":"A","T":"c","U":"7","V":"h","W":"v","X":"N","Y":"b","Z":"a"}, {"0":"x","1":"W","2":"q","3":"B","4":"j","5":"I","6":"E","7":"g","8":"U","9":"e","a":"8","b":"3","c":"5","d":"k","e":"9","f":"N","g":"7","h":"Q","i":"t","j":"r","k":"L","l":"Z","m":"b","n":"n","o":"Y","p":"H","q":"R","r":"6","s":"P","t":"1","u":"S","v":"M","w":"p","x":"l","y":"F","z":"2","A":"c","B":"T","C":"G","D":"h","E":"X","F":"v","G":"s","H":"O","I":"D","J":"4","K":"a","L":"A","M":"m","N":"d","O":"C","P":"f","Q":"V","R":"i","S":"o","T":"u","U":"w","V":"0","W":"K","X":"z","Y":"y","Z":"J"}, {"0":"x","1":"W","2":"q","3":"B","4":"j","5":"I","6":"E","7":"g","8":"U","9":"e","a":"8","b":"3","c":"5","d":"k","e":"9","f":"N","g":"7","h":"Q","i":"t","j":"r","k":"L","l":"H","m":"b","n":"n","o":"Y","p":"Z","q":"R","r":"6","s":"P","t":"1","u":"S","v":"M","w":"p","x":"l","y":"F","z":"2","A":"c","B":"T","C":"G","D":"h","E":"X","F":"v","G":"s","H":"O","I":"D","J":"4","K":"a","L":"A","M":"m","N":"d","O":"C","P":"f","Q":"V","R":"i","S":"o","T":"u","U":"w","V":"0","W":"K","X":"z","Y":"y","Z":"J"}]

# Changing my string characters
string_fin = ''.join(dicnums[i%4][c] for i,c in enumerate(string))

# Print result
print string_fin 

结果是 "SD11SD11SD11SD11SD11SD11SD11SD1" 如果我使用所有的 't's.如果我使 dict 范围更广，并且不重复使用相同的字符(我不会)，那么输出会好得多.一旦与我的加密概念的其余部分结合，我的程序可能实际上像我想要的那样工作.

The result is "SD11SD11SD11SD11SD11SD11SD11SD1" if i use all 't's. If i make the dict range broader, and am not using the same characters repeatedly(which i wont be) then the output would be much better. Once combined with the rest of my encryption concept, my program might actually work like i want.

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