从字符串中修剪特定的前导和尾随字符 [英] Trim specific leading and trailing characters from a string

问题描述

我有一个包含路径的字符串

I have a string that contains a path

str = "/example/path/with/different/trailing/delimiter\"

并且我想修剪前导和尾随 / 和 \.Python 3 中的最佳实践是什么?

and I want to trim the leading and trailing / and \. What is the best practice in Python 3?

目前我正在使用

trimmedPath = str.strip("/\\")
# trimmedPath is "example/path/with/different/trailing/delimiter" as desired

两个问题:

1. 这是在 Python 3 中修剪特定字符的最佳修剪函数吗?
2. Python 3 中是否有针对此类操作的特定路径函数，因此我不必手动设置分隔符?

推荐答案

我相信 strip 是 Pythonic 的方式.通常是有内置函数的情况.

I believe strip is the pythonic way. It is usually the case when there is a builtin function.

os 库.如果其中一个操纵器与您的用例匹配，您可能想要使用它们.

There are a few builtin path manipulators available in the os library. You might want to use them if one of the manipulators is a match for your use case.

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