杰克逊可以配置为从所有字符串属性修剪前导/尾随空格？ [英] Can Jackson be configured to trim leading/trailing whitespace from all string properties?

问题描述

示例JSON（请注意该字符串具有尾随空格）：

Example JSON (note that the string has trailing spaces):

{ "aNumber": 0, "aString": "string   " }

理想情况下，反序列化的实例将具有 aString 属性值为string（即没有尾随空格）。这似乎是可能支持的东西，但我找不到它（例如在 DeserializationConfig.Feature 中）。

Ideally, the deserialised instance would have an aString property with a value of "string" (i.e. without trailing spaces). This seems like something that is probably supported but I can't find it (e.g. in DeserializationConfig.Feature).

我们正在使用Spring MVC 3.x所以基于Spring的解决方案也没问题。

We're using Spring MVC 3.x so a Spring-based solution would also be fine.

我尝试根据论坛帖子但是在使用Jackson消息转换器时它似乎不起作用：

I tried configuring Spring's WebDataBinder based on a suggestion in a forum post but it does not seem to work when using a Jackson message converter:

@InitBinder
public void initBinder( WebDataBinder binder )
{
    binder.registerCustomEditor( String.class, new StringTrimmerEditor( " \t\r\n\f", true ) );
}

推荐答案

自定义反序列化程序，您可以执行以下操作：

With a custom deserializer, you could do the following:

 <your bean>
 @JsonDeserialize(using=WhiteSpaceRemovalSerializer.class)
 public void setAString(String aString) {
    // body
 }

 <somewhere>
 public class WhiteSpaceRemovalDeserializer extends JsonDeserializer<String> {
     @Override
     public String deserialize(JsonParser jp, DeserializationContext ctxt) {
         // This is where you can deserialize your value the way you want.
         // Don't know if the following expression is correct, this is just an idea.
         return jp.getCurrentToken().asText().trim();
     }
 }

这个解决方案确实暗示这个bean属性永远是以这种方式序列化，你必须以这种方式注释你想要反序列化的每个属性。

This solution does imply that this bean attribute will always be serialized this way, and you will have to annotate every attribute that you want to be deserialized this way.

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