杰克逊：忽略Json配置值 [英] Jackson: Ignore Json configuration value

问题描述

我有以下json文件：

I have the following json file:

{
  "segments": {        
            "externalId": 123, 
            "name": "Tomas Zulberti", 
            "shouldInform": true, 
            "id": 4
   }
}

但是java模型如下：

But the java model is as follows:

public class Segment {

    private String id;
    private String name;
    private boolean shouldInform;

    // getter and setters here...
}

当杰克逊解析时，它会引发异常，因为externalId字段没有getter或setter。它有一个可以用来忽略json字段的装饰器吗？

When Jackson is parsing it raises an exception becuase there is no getter or setter for the field "externalId". It there a decorator that can be used to ignore a json field?

推荐答案

你可以使用注释 @ JsonIgnoreProperties ;如果它只是你想要跳过的一个值，就像：

You can use annotation @JsonIgnoreProperties; if it's just one value you want to skip, something like:

@JsonIgnoreProperties({"externalId"})

或忽略任何无法使用的内容：

or to ignore anything that can't be used:

@JsonIgnoreProperties(ignoreUnknown=true)

还有其他方式为了休息，请查看 FasterXML Jackson wiki 。

There are other ways to do it too, for rest check out FasterXML Jackson wiki.

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